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Example 4 Video Example ) x2 + x - 3 Let y = Use the Quotient Rule to find y'. x3 + 8 Solution (43 y' = + 8). +x – 3 + x - 3) 8+ * (x³ + 8)2 (x3 + 8) 2х + 1 - (x2 + x - 3) 3x (x3 + 8)2 (x3 + 8) 2х - 1 3x4 – 3x + 9x? (x3 + 8)2 -x4 - 2x° + 9x2 + 16x + 8 (x3 + 8)2

Example 4 Video Example ) x2 + x - 3 Let y = Use the Quotient Rule to find y'. x3 + 8 Solution (43 y' = + 8). +x – 3 + x - 3) 8+ * (x³ + 8)2 (x3 + 8) 2х + 1 - (x2 + x - 3) 3x (x3 + 8)2 (x3 + 8) 2х - 1 3x4 – 3x + 9x? (x3 + 8)2 -x4 - 2x° + 9x2 + 16x + 8 (x3 + 8)2

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 36E
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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Differentiate. f(x) = (4x² – 3x)e* Step 1 Recall the product rule, where both g and h are differentiable. d d d + dx We are given the function f(x) = (4x2 - 3x)eX, which we see is the product of two differentiable functions g(x) and h(x) such that f(x) = g(x)h(x). If we let g(x) = 4x² – 3x, then h(x) is as follows. h(x) = 4x e* + 5xe* – 3e* | Submit Skip (you cannot come back).
Transcribed Image Text:This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Differentiate. f(x) = (4x² – 3x)e* Step 1 Recall the product rule, where both g and h are differentiable. d d d + dx We are given the function f(x) = (4x2 - 3x)eX, which we see is the product of two differentiable functions g(x) and h(x) such that f(x) = g(x)h(x). If we let g(x) = 4x² – 3x, then h(x) is as follows. h(x) = 4x e* + 5xe* – 3e* | Submit Skip (you cannot come back).
Example 4 Video Example ) x2 + x - 3 Let y = Use the Quotient Rule to find y'. x3 + 8 Solution (43 y' = + 8). +x – 3 + x - 3) 8+ * (x³ + 8)2 (x3 + 8) 2х + 1 - (x2 + x - 3) 3x (x3 + 8)2 (x3 + 8) 2х - 1 3x4 – 3x + 9x? (x3 + 8)2 -x4 - 2x° + 9x2 + 16x + 8 (x3 + 8)2
Transcribed Image Text:Example 4 Video Example ) x2 + x - 3 Let y = Use the Quotient Rule to find y'. x3 + 8 Solution (43 y' = + 8). +x – 3 + x - 3) 8+ * (x³ + 8)2 (x3 + 8) 2х + 1 - (x2 + x - 3) 3x (x3 + 8)2 (x3 + 8) 2х - 1 3x4 – 3x + 9x? (x3 + 8)2 -x4 - 2x° + 9x2 + 16x + 8 (x3 + 8)2
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