Exercise 14.85-Enhanced-with FeedbackMISSED THIS? Read Section 14.6 (Pa601 613)Watch KCV 14.0A solution containing 27 25 mg of an unknown proteinper 30.0 ml. of solution was found to have an osmoticpressure of 3.00 torr at 26 "CPart AWhat is the molar mass of the protein?Express your answer in grams per mole to three significant figures.VAZmolar mass=E/molSubmit Previs Answers Requ19 of 21

The osmotic pressure of a compound is related to the concentration and temperature as: π=c×R×T…

MISSED THIS? Read Section 146 (Pas 601 63 Watch KGV 14.6 A solution containing 27 25 ung of an unknown protein per 30.0 mL of solution was found to have an osmotic pressure of 3.60 torr at 26 "C Part A What is the molar mass of the protein? Express your answer in grams per mole to three significant figures. VAZ 0 2 molar mass= Submit Previs Answers t

MISSED THIS? Read Section 146 (Pas 601 63 Watch KGV 14.6 A solution containing 27 25 ung of an unknown protein per 30.0 mL of solution was found to have an osmotic pressure of 3.60 torr at 26 "C Part A What is the molar mass of the protein? Express your answer in grams per mole to three significant figures. VAZ 0 2 molar mass= Submit Previs Answers t

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section15.3: Solution Composition: Mass Percent

Problem 15.2SC

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Similar questions

5.Calculate the mole fraction of WATER in a solution of 45.0 grams of dextrose (molar mass = 180.158 g/mol) in 150.0 grams of water (molar mass = 18.0159 g/mol). Group of answer choices no correct answer 0.231 0.0291 0.972 0.769
What is the freezing point (in degrees Celcius) of 3.97 kg of water if it contains 151.6 g of CaBr2? The freezing point depression constant for water is 1.86 oC/m and the molar mass of CaBr2 is 199.89 g/mol. Type answer:
What is the molarity of a solution of NaF that is 14.% solute by mass and has a density of 1.20 g/mL?ml? [Show work]
The salt content was extracted from a 12.0000g junk food sample. The extract was diluted to 100.00mL. From this solution, 15.00mL was taken and required 23.75mL of a 0.08943M AgNO solution to reach the endpoint. What is the percentage by mass of salt as NaCI (58.45 g/mol) in the junk food sample? (Answer: 6.897% NaCl)
4.A 40.0 mg sample of a protein dissolved to give 50.00 mL of the solution has an osmotic pressure of 0.56 torr at 25oC. What is the molecular weight of the protein? R = 0.08206 (L)(atm)/(mol)(K) Group of answer choices no correct answer a, 5.4 x 104 b, 2.7 x 104 c, 2.7 x 102 d, 13.65
Activity 4: Aromatic Water Peppermint water (Simple solution method) Formula Peppermint oil ___ Purified water ___ To make 60ml Materials: Erlenmeyer flask, filter paper Procedure:
Which ion has the larger hydration energy, Na+ or K+ ?
A solution at 30°C contains 500 g of water and 59.0 g of sodium carbonate. The vapour pressure of pure water at this temperature is 0.0420 atm. What is the vapour pressure of water over the solution? Express your answer to three significant figures. p = Answer atm
The following table gives the concentration of norepinephrine ( mol per gram creatinine) in the urine of healthy volunteers in their early twenties. (show complete solution) follow up question: Is there any evidence that concentration of norepinephrine differs between thesexes?
Practice Exercise 1How many milligrams of sodium sulfide are needed to completelyreact with 25.00 mL of a 0.0100 M aqueous solution ofcadmium nitrate, to form a precipitate of CdS(s)?(a) 13.8 mg (b) 19.5 mg (c) 23.5 mg (d) 32.1 mg (e) 39.0 mg
A sample of sodium chloride, NaCl, weighing 0. 0678 g is placed in a 25.0-mL volumetric flask. Enough water is added to dissolve the NaCl, and then the flask is filled to the mark with water and carefully shaken to mix the contents. What is the molarity of the resulting solution?
The question is : Using benzoic acid's solubility data in water (found in pre-lab), calculate the amount of hot water needed to dissolve your crude benzoic acid. Based on your data and observation, explain why you may have used more ore less water than the calculated value. Pre lab Question: calculated amount of hot water to dissolve 2.0g of benzoic acid. => (2.0g benzoic acid)/( 68 g/L)(1000ml)/(1L) = 29.4 mL of hot water needed to dissolve 2.0g of benzoic acid. My cruse of benzoic acid is 1.81g.

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