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Find the value (1) for a solution (1 + 2x)y" + 4xy' – 4y = 0; y(0) = 1, y'(0) = −1 -2x is a solution to (1 + 2x)y” + 4xy' — 4y = 0. given that e (x) to the initial value problem: e-² ln 2 1+e-2 1-e-2

Find the value (1) for a solution (1 + 2x)y" + 4xy' – 4y = 0; y(0) = 1, y'(0) = −1 -2x is a solution to (1 + 2x)y” + 4xy' — 4y = 0. given that e (x) to the initial value problem: e-² ln 2 1+e-2 1-e-2

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 34CR
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Find the value (1) for a solution (1 + 2x)y" + 4xy' – 4y = 0; y(0) = 1, y'(0) = −1 -2x is a solution to (1 + 2x)y” + 4xy' — 4y = 0. given that e (x) to the initial value problem: e-² ln 2 1+e-2 1-e-2
Transcribed Image Text:Find the value (1) for a solution (1 + 2x)y" + 4xy' – 4y = 0; y(0) = 1, y'(0) = −1 -2x is a solution to (1 + 2x)y” + 4xy' — 4y = 0. given that e (x) to the initial value problem: e-² ln 2 1+e-2 1-e-2
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