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- Find the acceleration and % error gofficial=980 cm/ s^2 Question 1: If an object initially rest is dropped from height of 50 meters, how long will it take it to hit the ground and what is it's final speed when it hits the ground? Question 2: What if the same object is dropped on the moon whose acceleration is 1/6 that of earth, gmoon = 1.63 m/s^2. Answer the same question as #1find the instantaneous acceleration at t= 0.55 s given the displacement equation: x= t^4 - 2.8t^3 + 3.1t^2 + 4.4t -9.512–35. A freight train starts from rest and travels with a constant acceleration of 0.5 ft/s². After a time t' it maintains a constant speed so that when t = 160 s it has traveled 2000 ft. Determine the time t' and draw the v-t graph for the motion.
- The displacement of a particle is given by s=4t³-67t2 + 103t-66 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 14 seconds of motion. After you have made the plots, answer the questions. Questions: Att 3.7 sec, S= i Att - 6 sec, Att 10.1 sec, S= i SH i The velocity is zero when t = ft, v= i ft, v= i ft, v= i sec and when t= i ft/sec, a i ft/sec, a i ft/sec, a i sec ft/sec ft/sec ft/sec²The moton of an object (in meters)/s defined by the parametric equations X(E)=1-VE and Y (t) = - {2. Find the magnitude and direchon of the instantaneous velocity and acceleration at t=35ec , Cecundž decimal places) eg. x (t) = 1-SE eq. Y t) = - t2Determine s and a when t= 3 s if s=0 when t= 0. v (m/s) t (s) 4 2. 2.
- 2.68 0. CALC An object's velocity is measured to be v,(1) = a – Bt², . 4.00 m/s and B = 2.00 m/s. At t = 0 the object is at x = 0. (a) Calculate the object's position and acceleration as functions of time. (b) What is the object's maximum positive displacement from the origin? where a =I fill my tea mug (3.1” diameter and 7.5" tall) to 0.5" from the top and put it in the cup holder of my car without remembering to drink any. During my trip, I accelerate and decelerate smoothly (no hills, bumping, or sloshing). If the tea in the mug is 1" from the top when I get to my destination, the maximum acceleration was about ft/s2For the following motion equation s=2t^3 -15t^2+36t-22, t ⩾ 0 a. Find the average velocity and the average acceleration from t=2 to t=4
- The velocity of a particle is given by v = 21t2-82t - 263, where v is in feet per second and t is in seconds. Plot the velocity v and acceleration a versus time for the first 7 seconds of motion. After you have the plots, answer the questions as a check on your work. -1 Questions: + 0 + ++ 1 2 When t = 1.0 sec, V= When t = 6.0 sec, V = i + 3 -+s, ft or m When the acceleration is zero, the velocity is i ft/sec, ft/sec, a = a= i ft/sec. ft/sec² ft/sec²The acceleration of a particle is given by the equation: A=3×t if V=2 m/s at t=1 sec and S=12 m at t=1 sec. Find S at t=2 sec.Determine the maximum speed for each car if the normal acceleration is limited to 0.77g. The roadway is unbanked and level. Assume rд = 17 m, rg = 22 m. Answers: (VA)max= (VB)max = MO i by? m/s m/s