For the section shown in the Figure, calculate the shearing stresses at levels 50mm apart i V=5 kN. Zoom 200
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![(4) For the section shown in the Figure,
calculate the shearing stresses at levels.
apart it V=5KN.
50mm
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4
200
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- A strain rosette (see figure) mounted on the surface of an automobile frame gives the following readings: gage A,310 × 10-6:gage B,180 × l0-6; and gage C. -160 × 10-6. Determine the principal strains and maximum shear strains, and show them on sketches of properly oriented elements.An clement m plane stress from the frame of a racing car is oriented at a known angle 8 (sec figure). On this inclined clement, the normal and shear stresses have the magnitudes and directions shown in the figure. Determine the normal and shear stresses acting on an clement whose sides are parallel to the xy axes, that is, determine crv, tr(_, and t. Show the results on a sketch of an clement oriented at B = 10An clement m plane stress from the frame of a racing car is oriented at a known angle 8 (sec figure). On this inclined clement, the normal and shear stresses have the magnitudes and directions shown in the figure. Determine the normal and shear stresses acting on an clement whose sides are parallel to the \y axes, that is, determine crv, tr(_, and t, Show the results on a sketch of an clement oriented at B .
- The strains for an element of material in plane strain (see figure) are as follows: x = 480 ×10-6. y = 140 × l0-6, and xy = —350 x 10”. Determine the principals strains and maximum shear strains, and show these strains on sketches of properly oriented elements.The state of stress on an element of material is shown in the figure. Calculate the unit volume change of the element if the stresses x and y. are -20 ksi and 10 ksi, respectively. Assume E = 10,600 ksi and v = 0.33.The stresses acting on an element are x= 750 psi, y= 600 psi, and xy = 400 psi. Determine the principal stresses and show them on a sketch of a properly oriented element.
- Determine-- 1)maximum in-plane shear stress in Mpa. 2)direction of maximum shear stress in degree. 3)Determine the maximum absolute shear stress in Mpa. The state of plane stress at a point is represented by the element shown in the figure. 0: = 300 Mpa Oy = 450 Mpa Txy Tay = 200 Mpa Click here to see all formulas OxLearning Goal: The state of in-plane stress at a point on an element of material is shown. Let o = 55.0 ksi, oy = 16.0 ksi and Try = 10.0 ksi. Use this information to represent the state of stress of the same point that is rotated through an angle of 0 = 35° b b OT ▼ Part A - Normal and shear stress on element sectioned at plane a a Using the element sectioned at plane a-a and the rotated coordinate system shown, determine the normal and shear stresses, or and Try, respectively, acting on plane a-a ▼ Part B - Normal and shear stress on element sectioned at plane b-b Using the element sectioned at plane b-b and the rotated coordinate system shown, determine the normal Or Try and shear stresses acting on plane b-b. Express your answers in ksi to three significant figures separated by a comma. View Available Hint(s) VE ΟΙ ΑΣΦΑΛΙ b vec 0 ksiThe point A in the following plot represents: A or T 0.5 -180 -90 90 180° -0.50, Graph of normal & shear stresses on inclined angle
- From the stress states given, draw the 3D Mohr's circle (lable the principle normal stresses, maximum and absolute shear stresses), and sketch the principle and shear planes. σxx = 70 ksi, σzz = -50 ksi, ?xy = 50 ksi (counterclockwise)Draw Mohr's circle for the following plane strain state. Then compute (or extract from your drawing) the principal strains and max shear strain. (Positive sign convention for each is shown on the figure.) Ex = 200μ, Ey=-200μ, Yxy = 50μ (rad) You For the previous problem, compute the following six stress quantities: d. dy, dz. Txy, Tyz. Tzx. Assume this is an aluminum alloy (E = 10,000 ksi, G = 3800 ksi, v = 0.33). Do not forget units! ExProblem 3: For the plane stress state listed below, draw a Mohr's circle diagram properly labeled. Keep in mind that the principal stress is that stress state where the shear stress is zero. That means it is the stress state along the normal stress line in Mohr's space. So, use your Mohr's circle to find the principal normal and shear stresses, and determine the angle from the x axis to o1. 0x = 16 kpsi, oy = 9 kpsi, Ty = 5 kpsi ccw
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