Formic acid, HCOOH, ionizes in water according to the following equation. The equilibrium constantis K=1.8 × 10-4.HCOOH(aq) + H,O(D) — HCOO¯(aq) + H₂O + (aq)Calculate the equilibrium concentration of H3O+ in a 0.985 Msolution.M

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Formic acid, HCOOH, ionizes in water according to the following equation. The equilibrium constant is K= 1.8 x 10-4. HCOOH(aq) + H,O(1) HCOO-(aq) + HgO*(aq) Calculate the equilibrium concentration of H3O+ in a 0.985 M solution. M

Formic acid, HCOOH, ionizes in water according to the following equation. The equilibrium constant is K= 1.8 x 10-4. HCOOH(aq) + H,O(1) HCOO-(aq) + HgO*(aq) Calculate the equilibrium concentration of H3O+ in a 0.985 M solution. M

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter16: Solubility And Precipitation Equilibria

Section: Chapter Questions

Problem 70AP

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Question

Formic acid, HCOOH, ionizes in water according to the following equation. The equilibrium constant
is K=1.8 × 10-4.
HCOOH(aq) + H,O(D) — HCOO¯(aq) + H₂O + (aq)
Calculate the equilibrium concentration of H3O+ in a 0.985 Msolution.
M

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