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Identify the means and extremes of the following proportion. Then solve for m. 12 18 m 28 = 12 18 The extremes in the proportion == m 28 (Use a comma to separate answers as needed.) m= 12 18 The means in the proportion m 28 (Use a comma to separate answers as needed.) (Simplify your answer.) are = are

Identify the means and extremes of the following proportion. Then solve for m. 12 18 m 28 = 12 18 The extremes in the proportion == m 28 (Use a comma to separate answers as needed.) m= 12 18 The means in the proportion m 28 (Use a comma to separate answers as needed.) (Simplify your answer.) are = are

Mathematics For Machine Technology
Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter21: Direct And Inverse Proportions
Section: Chapter Questions
Problem 1A: Solve the proportion 3R=119for R. If necessary, round the answer to 3 decimal places.
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Identify the means and extremes of the following proportion. Then solve for m. 12 18 m 28 = 12 18 The extremes in the proportion == m 28 (Use a comma to separate answers as needed.) m= 12 18 The means in the proportion m 28 (Use a comma to separate answers as needed.) (Simplify your answer.) are = are
Transcribed Image Text:Identify the means and extremes of the following proportion. Then solve for m. 12 18 m 28 = 12 18 The extremes in the proportion == m 28 (Use a comma to separate answers as needed.) m= 12 18 The means in the proportion m 28 (Use a comma to separate answers as needed.) (Simplify your answer.) are = are
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