Give the SQL query and attach the output of the workbench after creating the table. Use the desc command to show the structure.
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Give the SQL query and attach the output of the workbench after creating the table. Use the desc command to show the structure.
![a) Table Name: Employee
Attribute
Data Type
Constraint
First Name
Varchar(15)
Not Null
Last Name
Varchar(15)
Not Null
SSN Number
Char(9)
Primary Key
Birthday
Date
Address
Varchar(50)
Sex
Char(1)
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- Member m = new BoardMember(); Is this statement legal or illegal and widening or narrowing conversion.C sharp Table: Student (the headers are the field names in the Students table) StudentID Name Age Gender ProgramID 791 Stephanie Brown 19 Female BCS 236 Shannon Dawn 25 Female BA 618 Geoff Berg 24 Male ARET 256 Andrew Schilling 22 Male BSC 902 Gary Sang 23 Male DAAD Note: There is a StudentDataSet with a Student table, a StudentTableAdapter, a StudentBindingSource, and a StudentDataGridView control on the form.Note: There is an Average query, named Average, that returns the average age of the student from the Student table.Note: There is also Max query, named Highest, that returns the highest age of the student from the Student table.Write the code you would place in the AverageButton click event on your form to call the Average query and the Highest query and display in a DifferenceLabel, the difference between the highest age of a student and the average age.//Need typed version please You are working with a database that stores information about suppliers, parts and projects. The Supply relation records instances of a Supplier supplying a Part for a Project. The schema for the database used in this question is as follows: ( primary keys are shown underlined, foreign keys in bold). SUPPLIER (SNo, SupplierName, City) PART (PNo, PartName, Weight) PROJECT (JobNo, JobName, StartYear, Country) SUPPLY (SNo, PNo, JobNo, Quantity) Provide relational algebra (NOT SQL) queries to find the following information. NOTE: You can use the symbols s, P, etc or the words ‘PROJECT’, ‘RESTRICT’ etc . do not need to try to make efficient queries – just correct ones. Where you use a join, always show the join condition. List the name of any part that was not used on a project that commenced in 2020. List the name of any part that has been supplied to all projects that commenced in 2020.
- Remaining Time: 13 minutes, 56 seconds. estion Completion Status: Which relationship does the following diagram represnt? savel) Player SaveFile O Association O Aggregation O Composition O Recursion Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers 33°C P Type here to searchPrimary keys and candidate keys may both be assigned to the same attribute.Attempt to view the structure of the HOMEWORK13 view.
- True or False : ___ Multiple Inheritance happens when a class has more than one sub-class. This problem can be observed in Programming Languages as well. ___ Given two relations named A and B, if we q-JOIN A and B, the maximum number of attributes in the result relation could be (the number of attributes of A) times(*) the number of attributes of B). ____ * in an SQL SELECT statement means “all the tuples”. ____ In relational algebra, Cartesian Product (X) can be implemented using the q-JOIN operator. Cartesian Product ISA q-JOIN where q-condition always evaluates to true. ____ SQL is based on Predicate Calculus. A query in SQL always specifies what should be included in the query result.branch(branchhame, branch+citysassets} customer (HD, Customer name, customer street, customer city) loan loan number branch_name, amounty borrower(ID; loan_number account (account_number, branch name, balance)e depositor (HDs account number)- Figure le Consider the bank database in Figure 1, where the primary keys are underlined. Each branch might have many loans or accounts, associated with borrowers or depositors, respectively. Construct the following SQL queries for this relational database. 1. Find the name of each branch that has at least one customer who has an account in the bank and who lives in the "Harrison" city. Make sure each branch name only appears once. 2. Find the ID of each customer who lives on the same street and in the same city as customer "12345". (1) Please use "tuple variables". e (2) Please use "derived relations" or “with". 3. Find the ID of each customer of the bank who has an account but not a loan. 4. Find the total sum of all loan amounts for each branch…Having this information. StudentsAttribute Name Data TypeStudentID char(11)FirstName varchar(20)LastName varchar(20)Gender char(1)DateofBirth date CoursesAttribute Name Data TypeCourseCode varchar(6)CourseName varchar(70)Level char(2)Credits int RegistrationAttribute Name Data TypeStudentID char(11)CourseCode varchar(6)Grade decimal(2, 1) Write SQL code to: 1. How many courses are there on each level? 2. What is the average grade of courses that have been taken by the student with student ID 861103-2438? 3. Which students (studentID only) have the highest grade for the course ‘CS052’? 4. Find the courses (course codes only) that have been taken by both the student 861103-2438 and the student 123456-0980.
- Having this information. StudentsAttribute Name Data TypeStudentID char(11)FirstName varchar(20)LastName varchar(20)Gender char(1)DateofBirth date CoursesAttribute Name Data TypeCourseCode varchar(6)CourseName varchar(70)Level char(2)Credits int RegistrationAttribute Name Data TypeStudentID char(11)CourseCode varchar(6)Grade decimal(2, 1) Write SQL code to: 1. What are the student ID, the names, and birthday of the female students who were born before the last day of 1992? 2. How many students are registered in the course “PHY210”? 3. How many courses are offered by the department of Computer Science (i.e. course codes CS***)? 4. Which course(s) (couseCode and courseName) of level G1 give 5 credits?Executed value?recurrence relation recurrence relationrecurrence relation
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