Given the following data 2 CIF (g) + O₂(g) → Cl₂ O(g) + F2O(g) ΔΗ= 167.4 kJ 2 CIF3 (9) +202 (g) → Cl₂ O(g) + 3F₂O(g) AH = 341.4 kJ 2F2₂(g) + O₂(g) →2F₂O(g) Δ Η = -43.4 kJ calculate A H for the reaction AH= CIF (g) + F2 (g) → CIF3 (9) Submit Answer kJ Try Another Version item attempt remaining

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Chapter1: Chemical Foundations
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### Thermochemistry Problem

Given the following data:

1. \( 2 \mathrm{ClF}(g) + \mathrm{O_2}(g) \rightarrow \mathrm{Cl_2O}(g) + \mathrm{F_2O}(g) \) 
   \[ \Delta H = 167.4 \, \text{kJ} \]

2. \( 2 \mathrm{ClF_3}(g) + 2 \mathrm{O_2}(g) \rightarrow \mathrm{Cl_2O}(g) + 3 \mathrm{F_2O}(g) \) 
   \[ \Delta H = 341.4 \, \text{kJ} \]

3. \( 2 \mathrm{F_2}(g) + \mathrm{O_2}(g) \rightarrow 2 \mathrm{F_2O}(g) \) 
   \[ \Delta H = -43.4 \, \text{kJ} \]

Calculate \(\Delta H\) for the reaction:

\[ \mathrm{ClF}(g) + \mathrm{F_2}(g) \rightarrow \mathrm{ClF_3}(g) \]

\[ \Delta H = \Box \, \text{kJ} \]

---

The interface has two buttons:
- **Submit Answer**
- **Try Another Version**

Additionally, there is an indication of the number of item attempts remaining: `1 item attempt remaining`.

### Explanation:

To solve for \(\Delta H\) of the given reaction, you can use Hess's Law which states that the total enthalpy change during the course of a reaction is the same whether the reaction takes place in one step or in several steps. 

You will need to manipulate the given reactions in such a way that, when combined, they will yield the desired reaction: 

\[ \mathrm{ClF}(g) + \mathrm{F_2}(g) \rightarrow \mathrm{ClF_3}(g) \]

You can use the given enthalpy changes (\(\Delta H\)) to determine the overall \(\Delta H\) for the reaction.
Transcribed Image Text:### Thermochemistry Problem Given the following data: 1. \( 2 \mathrm{ClF}(g) + \mathrm{O_2}(g) \rightarrow \mathrm{Cl_2O}(g) + \mathrm{F_2O}(g) \) \[ \Delta H = 167.4 \, \text{kJ} \] 2. \( 2 \mathrm{ClF_3}(g) + 2 \mathrm{O_2}(g) \rightarrow \mathrm{Cl_2O}(g) + 3 \mathrm{F_2O}(g) \) \[ \Delta H = 341.4 \, \text{kJ} \] 3. \( 2 \mathrm{F_2}(g) + \mathrm{O_2}(g) \rightarrow 2 \mathrm{F_2O}(g) \) \[ \Delta H = -43.4 \, \text{kJ} \] Calculate \(\Delta H\) for the reaction: \[ \mathrm{ClF}(g) + \mathrm{F_2}(g) \rightarrow \mathrm{ClF_3}(g) \] \[ \Delta H = \Box \, \text{kJ} \] --- The interface has two buttons: - **Submit Answer** - **Try Another Version** Additionally, there is an indication of the number of item attempts remaining: `1 item attempt remaining`. ### Explanation: To solve for \(\Delta H\) of the given reaction, you can use Hess's Law which states that the total enthalpy change during the course of a reaction is the same whether the reaction takes place in one step or in several steps. You will need to manipulate the given reactions in such a way that, when combined, they will yield the desired reaction: \[ \mathrm{ClF}(g) + \mathrm{F_2}(g) \rightarrow \mathrm{ClF_3}(g) \] You can use the given enthalpy changes (\(\Delta H\)) to determine the overall \(\Delta H\) for the reaction.
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