Given the Following information for a compound curve Leads with short curve I= 105°58'12" = 2,641.08 feet TL= Ts 2,110.17 feet = DL = 2°30'00" (chord definition) The length of the long curve, in feet, is: (Choose the most correct answer)

3 Horizontal curves You are asked to design a 5-degree horizontal curve with an intersection angle at the center equals 60°15'. The station of point of curvature is 155 + 26.5 ft. Calculate the following: A. Length of the curve B. Station of the point of tangency (PT) C. For first two whole stations next to PC, calculate the degree of deflection from the PC and chord length from the previous point along the horizontal curve.

Given the following spiral curve data: R= 220m; V= 80km/h; Δ = 28° 08’RT; PI@ 1+286.441; Two-Lane Road: Determine the value of each key spiral and horizontal curve component (Ls, X, Y, q, P, LT, ST, Lc, Δs, θs) using the charts provided, and determine the chainage of the T.S., S.C., C.S., and S.T. Note: Lc from table 11.9 represents the long chord of the spiral (not used in these calculations). Note: Although minimum radius is suggested to be 250m, we will continue to use a radius of 220m for this assignment. PLEASE USE THE GIVEN TABLES FOR VALUES. THANKS