If a graph is a parabola ['horseshoe' shape] opening up with a vertex [starting point] at (-5, -7) that only crosses the y-axis once at (0,18) and crosses the x-axis at both (-7.65,0) and at (-2.35,0): find the quadratic function for this graph, using the form f (x) = a(x – h)² + k, with a = 1 here. %3D O f(z) = (1 – 5)² + 7 O f(x) = (x + 7.65)² – 2.35 O f(z) = (z – 5)² – 7 O f(z) = (1 + 5) +7 O f(z) = (z + 5)² - 7
If a graph is a parabola ['horseshoe' shape] opening up with a vertex [starting point] at (-5, -7) that only crosses the y-axis once at (0,18) and crosses the x-axis at both (-7.65,0) and at (-2.35,0): find the quadratic function for this graph, using the form f (x) = a(x – h)² + k, with a = 1 here. %3D O f(z) = (1 – 5)² + 7 O f(x) = (x + 7.65)² – 2.35 O f(z) = (z – 5)² – 7 O f(z) = (1 + 5) +7 O f(z) = (z + 5)² - 7
Chapter9: Quadratic Equations And Functions
Section9.6: Graph Quadratic Functions Using Properties
Problem 9.104TI: A path of a toy rocket thrown upward from the ground at a rate of 208 ft/sec is modeled by the...
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![If a graph is a parabola ['horseshoe' shape] opening up
with a vertex [starting point] at (-5, -7) that only crosses
the y-axis once at (0,18) and crosses the x-axis at both
(-7.65,0) and at (-2.35,0):
find the quadratic function for this graph, using the form
f (x) = a(x – h)² + k, with a =
1 here.
%3D
O f(z) = (1 – 5)² + 7
O f(z) = (x + 7.65)² – 2.35
O f(z) = (z – 5)² – 7
O f(z) = (1 + 5) +7
O f(z) = (z +5) -7](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F485898ce-dbac-4a14-8c55-3f3ae529f33f%2Fbfc9c7ef-7e16-4f64-b3da-86f2c0f631bb%2Fg8ugn5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If a graph is a parabola ['horseshoe' shape] opening up
with a vertex [starting point] at (-5, -7) that only crosses
the y-axis once at (0,18) and crosses the x-axis at both
(-7.65,0) and at (-2.35,0):
find the quadratic function for this graph, using the form
f (x) = a(x – h)² + k, with a =
1 here.
%3D
O f(z) = (1 – 5)² + 7
O f(z) = (x + 7.65)² – 2.35
O f(z) = (z – 5)² – 7
O f(z) = (1 + 5) +7
O f(z) = (z +5) -7
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