If one of the planets in our solar system averages 0.723332 astronomical units from the sun, what is its orbital period (in Earth years, with one year = 365.256 Earth days)? the cubic root of (0.723332)1/2 = 0.947450 Earth years the square root of (0.723332)1/2 = 0.922220 Earth years the cubic root of (0.723332)1/3 = 0.964652 Earth years the square root of (0.723332)3 = 0.615186 Earth years the cubic root of (0.723332)2 = 0.805796 Earth years
If one of the planets in our solar system averages 0.723332 astronomical units from the sun, what is its orbital period (in Earth years, with one year = 365.256 Earth days)? the cubic root of (0.723332)1/2 = 0.947450 Earth years the square root of (0.723332)1/2 = 0.922220 Earth years the cubic root of (0.723332)1/3 = 0.964652 Earth years the square root of (0.723332)3 = 0.615186 Earth years the cubic root of (0.723332)2 = 0.805796 Earth years
Biology Today and Tomorrow without Physiology (MindTap Course List)
5th Edition
ISBN:9781305117396
Author:Cecie Starr, Christine Evers, Lisa Starr
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Chapter2: Molecules Of Life
Section: Chapter Questions
Problem 3CT: Polonium is a rare element with 33 radioisotopes. The most common one, 210Po, has 82 protons and 128...
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- If one of the planets in our solar system averages 0.723332 astronomical units from the sun, what is its orbital period (in Earth years, with one year = 365.256 Earth days)?
- the cubic root of (0.723332)1/2 = 0.947450 Earth years
- the square root of (0.723332)1/2 = 0.922220 Earth years
- the cubic root of (0.723332)1/3 = 0.964652 Earth years
- the square root of (0.723332)3 = 0.615186 Earth years
- the cubic root of (0.723332)2 = 0.805796 Earth years
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