Implement the following function using NOR gates only. Do not derive the K-map or truth table. Assume complemented inputs are available. f (a, b, c, d) = (b+d)(a+c +d')(b' +c' + d')
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- Create a circuit to generate odd parity bit for a 3-bit code. a. Construct the truth table. b. Use K-map to simplify the circuit. c. Draw the circuit with minimum number of gates. (I did the question myself, but I'm confused as to why the K-map does not provide the simplified circuit to build the minimum number of gates). Simplify the following Boolean algebraic expressions and draw a block diagram of the circuit for each simplified expression using AND OR and NOT gates. (a) AB’C’ + A’B’C’ + A’BC’ + A’B’C (b) A’BC + AB’C + A’BC + ABC’ + AB’C’ + A’BC’ + A’B’C’ (c) (A + B + C) (A + B’ + C’) (A + B + C’) (A + B’ + C)3- A-) Implement the Boolean function (F) with a 4 X1 multiplexer and two-input-NOR gates. Connect inputs A and B to the selection lines. The input requirement for the four data lines will be a function of variables C and D. These values are obtained by expressing F as a function of C and D for each of the four cases when AB = 00, 01 ,10 and 11. B-) Implement the Boolean function with a 8 X 1 multiplexer. Connect inputs A,B and C to selection lines. F(A, B, С, D) - 2 (1, 3, 5, 9, 10, 14, 15) А So В S1 4 x 1 MUX 1 Y F 2 3
- Task 6: Simplifying Boolean functions in EWB using the logic converter Simplify the following Boolean expression in EWB using the logic converter F (A, B, C) = AB'C'+ A'B'C'+ A'BC'+ A'B'CQuestion 4: For the number display below, we would like to identify Boolean expression for LEDS (outputs a through g2) that indicate numbers 11, 14, and 15. a. Please write the Boolean expressions for the two LEDS (outputs a through g2) based on the input signals So to S3. You do not need to simplify the Boolean expressions. b. Please draw the logit circuit for outputs a through g2 a2 Logic circuit 2. 88 5,5,5,504. Use the Word table tool to construct the truth table for this circuit. Be sure to include intermediate values. Insert column headings in the first row. Be sure to use the Insert > Equation tool so that standard Boolean logic symbols are displayed in the headings. A B. D In the circuit implementation of an 8-bit adder, explain why the carry bit connection of the least- significant bit is connected to ground. Explain in words what values for A, B, C, D, E will cause a 1 to appear at point X. A B E
- Q4: Need Asap please 0. Write Boolean expression For each Row in Table.1. Draw a k-map table based on the logic/truth table above. explain how you make k-map.2. Group the implicants (those 1s inside the k-map table) accordingly. Allowed groupings are 1, 2, 4, 8, 16, …, n.3. Write the Boolean expression based on the k-map table.4. Draw the logic gates diagram of the Boolean expression. Note:- please Solve with complete explanation.I Need step by step with explanation as I*m beginner in K-Map. will Surely Upvote. Will appreciate if Handwritten Solution.DISCUSSION: 1- Is the Gray code arithmetic code? Why? Where this code usėd? 2- What is the parity bit? 13- Design five - bit odd parity checker? 4- a) What are the main applications of the comparator? /b) Design two – two bit comparator. -5- Convert five.bit Gray to binary code, write truth table and draw the circuit diagram. 2-5F1 and F2 are Boolean function F1=ab'c+a'bc'+bc F2=ab'c+ab+a'bc' using an OR gate array P1 to P3 are product term in one or more variable a,a',b,b'c and c'.Find out terms P1,P2,and P3 P. Pa
- 5. Assume d3d₂d₁do is a BCD number and derive Boolean expression for segments b,c,e,f,g in a seven segment display in terms of d3d₂d₁do g 4 d Based on your boolean expressions derive the values of b,c,e,f,g segments when i. d3d₂d₁do= (0100) 2 ii. d3d₂d₁do = (0111)₂ iii. d3d2d₁do (1000)2In boolean algebra, the bar sign (-) indicates O a. NOT operation O b. OR operation O c. None of the options given O d. AND operationThere are 3 aircons installed in the main lobby. All the 3 aircons A,B,C work only under the condition that only one aircon works at any instance. Write the Boolean Expression using SOP and simplify it.