In each of the following problems (a) state, the null and the alternative hypothesis (b) compute the test statistic, (c) determine the critical value and sketch the rejection region and the non-rejection region using the normal curve. 1. The Head of the Mathematics Department announced that the mean score of Grade 11 students in the second periodic test in Statistics was 89, and the standard deviation was 12. One student believed that the mean score was less than this, so the student randomly selected 34 students and computed their mean score, and obtained a mean score of 85. At 0.01 level of significance, construct the critical regions.
In each of the following problems (a) state, the null and the alternative hypothesis (b) compute the test statistic, (c) determine the critical value and sketch the rejection region and the non-rejection region using the normal curve. 1. The Head of the Mathematics Department announced that the mean score of Grade 11 students in the second periodic test in Statistics was 89, and the standard deviation was 12. One student believed that the mean score was less than this, so the student randomly selected 34 students and computed their mean score, and obtained a mean score of 85. At 0.01 level of significance, construct the critical regions.
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
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In each of the following problems (a) state, the null and the alternative hypothesis (b) compute the test statistic, (c) determine the critical value and sketch the rejection region and the non-rejection region using the normal curve.
1. The Head of the Mathematics Department announced that the mean score of Grade 11 students in the second periodic test in Statistics was 89, and the standard deviation
was 12. One student believed that the mean score was less than this, so the student randomly selected 34 students and computed their mean score, and obtained a mean score of 85. At 0.01 level of significance, construct the critical regions.
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