In order to replace the code snippet, create a new function and use recursive principles.
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In order to replace the code snippet, create a new function and use recursive principles.
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- 3 6. 9 12 15 ListB 1 2 3 Based on above memory illustrations. Complete these following fragment code: (i), (ii), (iii) Hint : Array ListB is the manipulation of array ListA. int ListA[5] = // (i) initialization of array ListA int ListB[5]; for( int i = 0; i++){ //(ii) control expression for maximum index ListB[i] = ;//(ii) manipulate elements ListA to save in ListB cost }Exercise 11.4. ¤ Write a function in Python that takes two inputs: • a list of points in R", a positive integer d, and returns the degree-d least squares approximation to the input points. You may use the solve command from numpy.linalg or scipy.linalg.int a[100], b[1000], c[1000]; // get some data for a, b, and c for (i = 0; i < 100; i++) for (j = 0; j < 10; j++) a[i] += c[j*100 + i] * b[j*100 + i] ;
- (5) {w € [0, 1]* : none of the prefixes of w ends in 0} Testing strings: €, 0, 1, 00, 01, 10, 11, 110, 101, 111 The accepted strings are: [] J n [] U [] W O 1 00 01 10 11 110 101 1111. Trace the execution of the following: {0, 1, 2, 3, 4, 5, 6, 7}; int[] anArray for (int i = 3; i 3; i--) 1]; What are the contents of anArray after the execution of each loop?4.2.16 removeRepeats (mutating and nonmutating) EF D E F Q from cmu_cs3_utils import testFunction 1 2 3 def mutatingRemoveRepeats (L): 4 return 42 5 6 7 8 9 10 def testMutatingRemoveRepeats(): 11 L = [1, 5, 2, 2, 4, 4, 21 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 def nonmutatingRemoveRepeats (L): return 42 @testFunction 42 43 44 mutatingRemoveRepeats (L) assert (L == [1, 5, 2, 4]) L = [-2, 15, -2, 3] mutatingRemoveRepeats (L) assert (L= [-2, 15, 3]) L = [1, 1, 1] mutatingRemoveRepeats (L) assert (L [1]) L = [1, 9, 5] mutatingRemoveRepeats (L) assert (L == [1, 9, 5]) L = [] mutatingRemoveRepeats (L) assert (L= []) assert (mutatingRemoveRepeats (L) == None) 31 32 33 @testFunction 34 35 36 37 38 39 40 41- def testNonmutatingRemoveRepeats(): assert (nonmutatingRemoveRepeats ([1, 5, 2, 2, 4, 4, 2]) == [1, 5, 2, 4]) assert (nonmutatingRemove Repeats([-2, 15, -2, 3]) == [-2, 15, 31) assert(nonmutatingRemoveRepeats([1, 1, 1]) == [1]) assert (nonmutatingRemoveRepeats([1, 9, 5])…
- (4) {w € [0, 1]* : w does not have 001 as a substring} Testing strings: €, 0, 1, 01, 000, 001, 0001, 0010, 0101, 11000, 110010 The accepted strings are: L U E O 01 000 001 0001 ☐ 0010 0101 11000 110010•• P11.6 Refine the is_palindrome function to work with arbitrary strings, by ignoring non-letter characters and the distinction between upper- and lowercase letters. For example, if the input string is "Madam, I'm Adam!" then you'd first strip off the last character because it isn't a letter, and recursively check whether the shorter string "Madam, I'm Adam" is a palindrome.Q2-Consider the following code fragment. i-m-1; j=n; v=a[n]; while (true) { do i=i+1; while( a[i] v); i(i >= j) break; x=a[i]; a[i]=a[j]; a[j]=x; } x=a[i]; a[i] = a[n]; a[n] =x; a) Translate the above code into three address statements: b) Construct a control flow graph of the three address statements generated in part a)
- • R7.6Given the definitions double primes[] = { 2, 3, 5, 7, 11, 13 }; double* p = primes + 3; draw a diagram that explains the meanings of the following expressions: a.primes[1] b.primes + 1 c.*(primes + 1) d.p[1] e.p + 1Q5.1 Write a program E2b Write a Java program called E2b that will read from Stdln an integer, n, and will set the size of a 2D array to have n rows and n columns. The values in this n xn 2D array must be read from Stdln and the array must be filled in row-major order. For example, if the following input stream was read: 4 1234 4321 9876 5764 The 2D array created would be: 2 4 3 2 1 9. 8 7 6 4 Include in the program above, code that would print the values in the 2D array beginning with the value in the last row, last column and ending with the value in the Oth row, Oth column, traversing the columns from bottom to top, printing n values in each row of the output. The values In the array do not change. You are simply printing them in a unique order. For example, for the array given above, the output would be: 4 6 1 4 6 7 8 3 2 4 1 public class E2b public static void main(String[] args) // WRITE YOUR CODE HERE Enter your answer hereIn [13]: def isAbundant (x): ***Returns whether or not the given number x is abundant. A number is considered to be abundant if the sum of its factors (aside from the number) is greater than the number itself. Example: 12 is abundant since 1+2+3+4+6-16 > 12. However, a number like 15, where the sum of the factors. is 1 + 3 + 5 - 9 is not abundant. your code here sum-1 for i in range(2,x) if(x1==0): Bum-Bum+1 if(sum>) 1 print(x, 'is Abundant Number") else: print (x, 'is not Abundant Number') File "", line 19 else: SyntaxError: invalid syntax In [14]: abundant_numbers [12, 18, 20, 24, 30, 36, 40, 42, 48, 54, 56, 60, 66, 70, 72, 78, 80, 84, 88, 90, 96, 100, 102, 104, 108, 112, 114, 1201 for i in abundant numbers assert true (isAbundant (i), str(i) is abundant") not abundant_numbers [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17, 19, 21, 22, 23, 25, 26, 27, 28, 29, 91, 92, 93, 94, 95, 1191 for i in not abundant_numbers: assert true (not (isAbundant (i)), str(i) is not abundant")…