In the figure circuit section AB absorbs energy at a rate of 39 W when current i = 0.91 A through it is in the indicated direction.Resistance R = 2.0 Q. (a) What is the potential difference between A and B? Emf device X lacks internal resistance. (b) What is its emf?AR(a) NumberUnits(b) NumberUnits

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In the figure circuit section AB absorbs energy at a rate of 39 W when current i = 0.91 A through it is in the indicated direction. Resistance R = 2.00. (a) What is the potential difference between A and B? Emf device X lacks internal resistance. (b) What is its emf? A R (a) Number Units (b) Number Units

In the figure circuit section AB absorbs energy at a rate of 39 W when current i = 0.91 A through it is in the indicated direction. Resistance R = 2.00. (a) What is the potential difference between A and B? Emf device X lacks internal resistance. (b) What is its emf? A R (a) Number Units (b) Number Units

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter18: Direct-Current Circuits

Section: Chapter Questions

Problem 50AP: Three 60.0-W, 120-V lightbulbs are connected across a 120-V power source, as shown in Figure P18.50....

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Power P0 = I0 V0 is delivered to a resistor of resistance R0. If the resistance is doubled (Rnew = 2R0) while the voltage is adjusted such that the current is constant, what are the ratios (a) Pnew/P0 and (b) Vnew/V0? If, instead, the resistance is held constant while Pnew = 2P0, what are the ratios (c) Vnew/V0, and (d) Inew/I0?
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