IR Spectrum (liquid film) ..لا 4000 8000 60 % of base peak 3000 57 91 40 80 40 20 13C NMR Spectrum (50.0 MHz, CDCI, solution) 92 8 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 2000 120 V (cm¹) M+ 148 160 m/e 160 wapm 1600 1200 7 200 240 120 800 Mass Spectrum C11H16 280 solvent 80 6 expansion 7.5 7.0 I 5 4 Problem 97 ppm UV Spectrum max 260 nm (log₁08 2.5) solvent: methanol 40 f 1 3 2 08 (ppm) TMS L 0 8 (ppm) 1 203

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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IR Spectrum
(liquid film)
4000
100
80
زار
60
40
20
stelldefels
% of base peak
3000
40
57
91
13C NMR Spectrum
(50.0 MHz, CDCI, solution)
92
DEPT CH₂ CH₂ CH
proton decoupled
200
¹H NMR Spectrum
(200 MHz, CDCI, solution)
10
9
1
2000
V (cm¹)
8
80 120 160
k
160
M+
m/e
M
148
7
1600
200
IL
6
120
800
Mass Spectrum
C11H16
280
solvent
J
1200
240
expansion
7.5
I
1
5
L
80
7.0
I
4
1
ppm
3
Problem 97
UV Spectrum
max 260 nm (log10 2.5)
solvent methanol
40
I
2
0
1
8 (ppm)
TMS
L
0
8 (ppm)
203
Transcribed Image Text:IR Spectrum (liquid film) 4000 100 80 زار 60 40 20 stelldefels % of base peak 3000 40 57 91 13C NMR Spectrum (50.0 MHz, CDCI, solution) 92 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 1 2000 V (cm¹) 8 80 120 160 k 160 M+ m/e M 148 7 1600 200 IL 6 120 800 Mass Spectrum C11H16 280 solvent J 1200 240 expansion 7.5 I 1 5 L 80 7.0 I 4 1 ppm 3 Problem 97 UV Spectrum max 260 nm (log10 2.5) solvent methanol 40 I 2 0 1 8 (ppm) TMS L 0 8 (ppm) 203
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