LO 78- Explain how organismal phenotypes can be influenced by more than one gene. Select the statements that are true about inheritance patterns of phenotypes Organismal traits can be monogenic or polygenic A gene can only affect one trait at a time Several regulatory genes can be related to several structural genes, giving rise to many possible phenotypes Pleiotropy is the existence of a wide range of phenotypes for a single trait In Mendelian inheritance, a single gene codes for a molecule which affects a single trait

LO 78- Explain how organismal phenotypes can be influenced by more than one gene. Select the statements that are true about inheritance patterns of phenotypes Organismal traits can be monogenic or polygenic A gene can only affect one trait at a time Several regulatory genes can be related to several structural genes, giving rise to many possible phenotypes Pleiotropy is the existence of a wide range of phenotypes for a single trait In Mendelian inheritance, a single gene codes for a molecule which affects a single trait

Name: LO 78- Explain how organismal phenotypes can be influenced by more th
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: LO 78- Explain how organismal phenotypes can be influenced by more than one gene.Select the statements that are true about inheritance patterns of phenotypesOrganismal traits can be monogenic or polygenicA gene can only affect one trait at a timeSev

Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter19: Introduction To Genetics

Section: Chapter Questions

Problem 9SQ

See similar textbooks

Similar questions

A1) The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and is heterozygous for hitchhikers thumb. What fraction of this couple's children should have no widow's peak and no hitchhiker's thumb? 1/4 1/8 1/2 3/8 3/4 A2)Using the forked line method, determine the phenotypic ratio of a trihybrid cross between AaBbCc X AaBBCC. What proportion of offspring will have the dominant phenotype for A, B, and C? 1/8 1/4 1/16 3/4 1/2 A3) How many different offspring genotypes are expected in a trihybrid cross between parents heterozygous for all three traits when the traits behave in a dominant and recessive pattern? How many phenotypes? 8 genotypes; 27 phenotypes 27 genotypes; 8 phenotypes 16 genotypes; 64 phenotypes 64 genotypes; 16 phenotypes
Genotype refers to the letters used as symbols for the genes. Phenotype refers to the appearance.Let’s practice assigning letters for the tall and short phenotype. Remember, we usually use the letter of the dominant (trait).
A1) The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and is heterozygous for hitchhikers thumb. What fraction of this couples children should have a widow's peak and a hitchhiker's thumb? 3/8 1/4 1/2 3/4 0 A2)The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and has no hitchhikers thumb. What fraction of this couple's children should have no widow's peak and a hitchhiker's thumb? 3/8 0 1/4 1/2 1/8
C. Give the genotypic and phenotypic ratios 1. Hemophilia is a disease caused by a gene found on the X chromosome. The recessive allele causes the disease. Tall (T) is dominant over short (t). A homozygous tall female carrier marries a short hemophiliac male. Predict the genotype and phenotype of their offspring. 2. In mice, the ability to run normally is a dominant trait. Mice with this trait are called running mice (R). The recessive trait causes mice to run in circles only. Mice with this trait are called waltzing mice (r). Hair color is also inherited in mice. Black hair (B) is dominant over brown hair (b). 2 heterozygous running, heterozygous black mice were crossed. Give the genotypic and phenotypic ratios of their offspring.
PKU is a recessive disorder based on a single mutant gene. Consider that Noor is a carrier, but her partner Hamza has never had an incidence of PKU show up in his family history, which dates back to four generations. What is the likelihood their first child might develop PKU according to their genetics counselor? a) 100%! b) 50% c) 25% d) 0%
Cystic fibrosis is an autosomal recessive disorder that affects 1 in 3 000 newborns with Caucasian background. It causes thick mucus build up in various organs and can cause damages and problems in respiratory and digestive systems. a) What is the frequency of the cystic fibrosis allele in the Caucasian population? Show all your work and express your answer as a value between 0 and 1 rounded to two decimal places. b) What percentage of the Caucasian population would be carriers for cystic fibrosis? Show all your work and express your answer rounded to two decimal places. c)If two individuals are carriers of the cystic fibrosis allele, what is the probability that they would have a girl without cystic fibrosis? Show all your work (including the Punnett square) and express your answer as a value between 0 and 1 rounded to two decimal places.
Color blindness is typically an inherited genetic condition in which individuals have a decreased ability to see color or differences in color. Color blindness only occurs in individuals who have two recessive alleles for the condition. Normal color vision is due to a dominant allele (C) Color blindness is due to the recessive allele (c) a) If Susan is homozygous for normal vision, and Matt is homozygous for color blindness, what is the likelihood (in percentage) that their son Alex will have color blindness? Perform a Punnett Square (either below or by hand on paper) to find the probability. Provide your answer in a full sentence. If you did the Punnett Square by hand, attach your photo to the next question.
please choose correct letter and discuss why you choose it.thanks 1. which among the traits is easier to control genetically? a. number of eggs per clutch b. egg weight 2. which among the statements about genetic correlation is true? a. always b. closely linked genes tend to stay together over several generations c. shown when genes have high penetrance d. none of the above 3. The part of the genotypic value that can be directly transmitted from parents to offspring? a. breeding value b. gene combination value c.environmental value d. none of the above
96% of Florida panther population has normal tails. 4% of the Florida panther population has the crook in the tail. Crooked tails are recessive. Find the dominant allele frequency and the recessive allele frequency. Construct a Punnett Square that would illustrate the phenotypic outcome of the a parent who is homozygous for a normal tail and homozygous for a crooked tail.  Include a Punnett square illustrating the cross.  Include a “key” or “legend” describing the pattern of inheritance for the trait, the genotypes of the parents, and the phenotypic percentages of the outcome of the cross.
A phenotypically normal couple has had one normal child and one child with cystic fibrosis, an autosomal recessive disease. What are the genotypes of the parents? What is the chance that their next child will be a carrier of cystic fibrosis?Many recessive traits are very rare in a population, but cystic fibrosis does not follow this pattern. In some populations, the frequency of carriers for cystic fibrosis is 1/35. Does this mean that cystic fibrosis is not more common in inbred mating, such as those between first cousins? Why or why not?
Homozygous dominant parent (PP), and a Homozygous recessive or just simply say recessive parent (pp): a. Fill in the Punnett square. Each box represents a genotype possibility for an offspring. b. Place the allele donated by each parent in the corresponding box. Now list the possible genotypes and their corresponding phenotype. c. If an individual's genotype is heterozygous, the dominant trait will be expressed in the phenotype. Give the percent possible for the phenotypes. P P p p Genotype: ______________ Phenotype: ______________ Phenotype % probable: __________ 2. Cross between a Homozygous dominant parent (PP) and a Heterozygous parent (Pp). Fill in as in step one. 3. Cross between a Heterozygous parent (Pp), and another Heterozygous parent (Pp). Fill-in as before. 4. Test cross: A test cross is between a recessive parent (pp), and a Heterozygous parent…
5. Brown eye color is an example of a while heterozygous is an example of a 1. Genotype; phenotype 2. Phenotype; genotype