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- A male rabbit with the genotype GgBb is crossed with a female rabbit with the genotype GgBb. Fill out the squares below and determine the phenotypes and proportions of the offspring.Fruit fly body color is wild type (meaning normal) Gray = B+ and black = b Fruit fly wing type is wild type normal wings = vg+ and vg = vestigial A fly which was heterozygous for both traits was crossed with a fly that was recessive for both traits. Write the genotype and phenotype that would be expected from this cross. Write the genotype and phenotype percentages that would be expected from this cross.you perform a cross of two heterozygous, red-eyed flies. They have 100 offspring. How many of these offspring do you predict will have red eyes? Show your work using a Punnett square. [Use letters R and r to designate the alleles]
- The table below shows the progeny of a test cross of a heterozygote (MmRrDd). Each row shows the number of progeny that inherited each combination of alleles from the heterozygous parent. Which combinations of alleles represent a single crossover? Choose all that apply. Alleles Number mRd Mrd mrd mrD MRD MRd mRD MrD mRD m Rd mrD OMRd Mrd mrd MRD MrD 8 110 38 29 42 31 107 6Produce a Punnett square to illustrate the dihybrid cross described below (NOTE: It is the same story as in question 9, above so you may use the square that you produced in answer to question 9 to answer this question, you do not need to draw it twice). use it to fill in the blanks in the answer text below. NOTE: please type in whole numbers only, no symbols, no letters, no spaces. There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles, meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the…Make a cross of four o’clock plant (Mirabilis jalapa L.) with red and white flowers. Get the F1 and F2 (by selfing F1), genotypic and phenotypic ratios. Show the phenotypic ratio by means of color.
- Snapdragons (a type of flower) are incompletely dominant for color; they have phenotypes red, pink, or white. The red flowers are homozygous dominant, the white flowers are homozygous recessive, and the pink flowers are heterozygous. Give the genotypes for each of the phenotypes, using the letters “R" and "w" for alleles. c. White snapdragon a. Red snapdragon Genotype: b. Pink snapdragon Genotype: Genotype: Show genetic crosses between the following snapdragon parents, using the Punnett squares provided, and record the genotypic and phenotypic ratios. a. Pink x pink b. red x white c. pink x white Genotypic ratio: Genotypic ratio: Genotypic ratio: Phenotypic ratio: Phenotypic ratio: Phenotypic ratio:Using a Punnet square, perform a trihybrid cross on the following traits in hybrid form: Height - Tt Flower color - Pp Seed shape - Ss Give the phenotypic and genotypic ratio.In pea plants, the tall allele is dominant to the short allele and the yellow pea allele is dominant to the green pea allele. Complete the Punnett square and questions below using the information and parent cross below. TtYy x TTyy 1. Complete the Punnett squares below. T Y y TT Tt yy TT Tt Yy yy 2. The phenotypes for TTYY and TtYy are correct order to receive credit T-trait listed first then the Y-trait) and (make sure the traits are listed in the 2a. What is the chance of an offspring having these two traits? 3. The phenotype for ttyy is and (make sure the traits are listed in the correct order to receive credit T-trait listed first then the Y-trait) 3a. What is the chance of an offspring having these two traits? :: T :: Y :: y :: TT :: Tt :: tt :: YY :: Yy : yy :: tall :: short : yellow :: green : 0% : 12.5% :: 25% : 37.5% :: 50% :: 56.25% :: 75% :: 100%
- Andalusian chickens have one allele for white feathers and one allele for black feathers – they display codominance. When they are crossed the heterozygous offspring have black and white checkered feathers (BW). Pure chickens are either black (BB) or white (WW). Cross an Andalusian (heterozygous) chicken with a white chicken. Make a Punnett Square on a piece of paper that will help you answer the question. What percentage of the offspring will be black? What percentage of the offspring will be white? What percentage of the offspring will be andalusian?Write down symbols for the alleles. (These may be given in theproblem.) When represented by single letters, the dominantallele is uppercase and the recessive is lowercase.Produce a Punnett square to illustrate the dihybrid cross described below (NOTE: It is the same story as in question 9, above so you may use the square that you produced in answer to question 9 to answer this question, you do not need to draw it twice). use it to fill in the blanks in the answer text below. NOTE: please type in whole numbers only, no symbols, no letters, no spaces. There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles, meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the…