SOLVE mathematically and give logical reason. Number of grams of Ca3(PO4)2 and grams of KCl is....can be produced by mixing 5g of CaClz with 8g ofК.РОд ассording to 3CaClz + 2 K,РОД — Саз(РО4)2 + 6KCI (М.Wt CaCl%3110, К,РО3212 ,КС-74,Ca3(PO4)2=310)а- Саз (РО4)2 6.7g, КСC-4.7gd- KCI= 6.7g, Ca3(PO4)2= 4.7gb- KCI-3.36g, Ca;(PO4)2=2.35g c- Ca3(PO4)2=3.36g, KCI-2,35ge- none of themc 190

To calculate the grams of the product obtained. First of all we have to determine the limiting…

Number of grams of Ca3(PO4)2 and grams of KCI is....can be produced by mixing 5g of CaCl2 with 8g of K;PO4 according to 3CaCl2 + 2 K;PO4 Ca3(PO4)2 + 6KCI (M.Wt CaCl-110, K3PO4-212 ,KCI=74, Ca3(PO4)2-310) a- Ca3(PO4)2-6.7g, KCI-4.7g b- KCI=3.36g, Ca3(PO4)2=2.35g c- Ca3(PO4)=3.36g, KCI=2.35g d. KC- 67g Co.(PO thom one

Number of grams of Ca3(PO4)2 and grams of KCI is....can be produced by mixing 5g of CaCl2 with 8g of K;PO4 according to 3CaCl2 + 2 K;PO4 Ca3(PO4)2 + 6KCI (M.Wt CaCl-110, K3PO4-212 ,KCI=74, Ca3(PO4)2-310) a- Ca3(PO4)2-6.7g, KCI-4.7g b- KCI=3.36g, Ca3(PO4)2=2.35g c- Ca3(PO4)=3.36g, KCI=2.35g d. KC- 67g Co.(PO thom one

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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