|J V10- J-V16 z² - (2² + y² + z²)!/2 Evaluate the integral. 16-z2 16-2 1 dy dz da = /16 z2 16 z (x² + y² + z²)1/2
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- Find integral of ydy/square root of y + 2 using the substitution u + 5 = square root of y + 2.Evaluate the integral. Sx +2 dx 8x +2 -(64x²+16x-66)+ Cc a. 512 b. e 8x +2 -(64:²-16x - 66)+ C 512 e Sx +2 C. -(64x2-16x +66)+c 64 e 8x +2 (64x²+16x-66)+C d. е. e Sx +2 312 (64x? - 16x + 66) +cSketch the region whose area is given by the definite integral. dx - 3 2.5 2 1.5 0.5 -3 -2 -1 1 1 3 4. 2.5- yA.5 y 2
- Evaluate the integral: (9z²+7=) dr +C (r-1)(r+1)-3y2-3x²+9 SE sirsa S*** Conyert 2x - 9y dzdydx to integral of cyclındrı cal coordinate then evaluateEvaluate the integral. 5x а. e (25x2-10x + 198)+c 125 Ob. (25x²+10x-202)+c 125 e -(25x²– 10x – 201)+ c c. 5 d. O d. esx (25x2-10x+202)+c 125 e. esx е. (25x²-10x-198)+c 125