||H(ej«)| = {1, Q3: The frequency response of an ideal low-pass filter is: - 1, π/4≤w ≤ π/4 . otherwise and ZH(ejw) = S-π/2, w≥O π/2, ω < 0 a) Calculate the impulse response h(n) of the filter. 30 Mark 35 Mark b) If the above filter is connected in series with a defective sinusoidal signal generator that gives sinusoids of x(n) = 1.5 cos (2nπ/3), for what frequency (or frequencies) is the filter output y(n)? N-I Σαπ = 1-a N 1-a 1 a" tal < 1 =0 a * Use the expressions in the table as much as it is needed. N-I Σna" = (N-1)a+ Na + a (1 - a)² a na" = la <1 (1 - a)² л N-I A=0 N-I Στ= ( - 1) = ΣN(N-1)(2N - 1) ло A=0

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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||H(ej«)| = {1,
Q3: The frequency response of an ideal low-pass filter is:
-
1, π/4≤w ≤ π/4
.
otherwise
and ZH(ejw) = S-π/2,
w≥O
π/2,
ω < 0
a) Calculate the impulse response h(n) of the filter.
30 Mark
35 Mark
b) If the above filter is connected in series with a defective sinusoidal signal generator that gives sinusoids of
x(n) = 1.5 cos (2nπ/3), for what frequency (or frequencies) is the filter output y(n)?
N-I
Σαπ
=
1-a N
1-a
1
a"
tal < 1
=0
a
* Use the expressions in the table as much as
it is needed.
N-I
Σna" =
(N-1)a+ Na + a
(1 - a)²
a
na" =
la <1
(1 - a)²
л
N-I
A=0
N-I
Στ= ( - 1)
=
ΣN(N-1)(2N - 1)
ло
A=0
Transcribed Image Text:||H(ej«)| = {1, Q3: The frequency response of an ideal low-pass filter is: - 1, π/4≤w ≤ π/4 . otherwise and ZH(ejw) = S-π/2, w≥O π/2, ω < 0 a) Calculate the impulse response h(n) of the filter. 30 Mark 35 Mark b) If the above filter is connected in series with a defective sinusoidal signal generator that gives sinusoids of x(n) = 1.5 cos (2nπ/3), for what frequency (or frequencies) is the filter output y(n)? N-I Σαπ = 1-a N 1-a 1 a" tal < 1 =0 a * Use the expressions in the table as much as it is needed. N-I Σna" = (N-1)a+ Na + a (1 - a)² a na" = la <1 (1 - a)² л N-I A=0 N-I Στ= ( - 1) = ΣN(N-1)(2N - 1) ло A=0
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