Answered: Out of 100 people sampled, 48 had kids.…

Out of 100 people sampled, 48 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places < p <

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Out of 500 people sampled, 380 had kids. Based on this, construct a 90% confidence interval for the…

Q: Out of 200 people sampled, 188 had kids. Based on this, construct a 95% confidence interval for the…

A: Given information- Confidence level, c = 95% Sample proportion is,

Q: Out of 200 people sampled, 62 had kids. Based on this, construct a 95% confidence interval for the…

Q: Out of 100 people sampled, 84 had kids. Based on this, construct a 95% confidence interval for the…

A: Introduction: The 100 (1 – α) % confidence interval for the population proportion, p is: Here, n is…

Q: Out of 500 people sampled, 390 had kids. Based on this, construct a 99% confidence interval for the…

A: Find z-critical value: For the two-tail test, Area on each tail. Area to the left of the normal…

Q: Out of 600 people sampled, 228 had kids. Based on this, construct a 90% confidence interval for the…

A: The following information is given Sample size n=600 Number of kids x= 228 Proportion p^=228600=0.88…

Q: Out of 400 people sampled, 344 had kids. Based on this, construct a 99% confidence interval for the…

A: Given that sample size n = 400 Number of peoples with kids, X = 344 The critical value of Z at 99%…

Q: Out of 400 people sampled, 232 had kids. Based on this, construct a 95% confidence interval for the…

Q: Out of 400 people sampled, 240 had kids. Based on this, construct a 95% confidence interval for the…

Q: Out of 300 people sampled, 138 had kids. Based on this, construct a 90% confidence interval for the…

A: Given data, n=300 x=138 p=x/n=138/300 =0.46 z-value at 90% confidence is Zc=1.645

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: Out of 200 people sampled, 72 had kids. Based on this, construct a 90% confidence interval for the…

A: Givensample size(n)=200x=72sample proportion(p^)=xn=72200=0.36Confidence level=90%

Q: Out of 600 people sampled, 486 had kids. Based on this, construct a 95% confidence interval for the…

A: It is given that Favourable cases, X = 486 Sample size, n = 600

Q: Out of 400 people sampled, 244 had kids. Based on this, construct a 95% confidence interval for the…

Q: Out of 200 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: Out of 600 people sampled, 480 had kids. Based on this, construct a 95% confidence interval for the…

A: given that , out of 600 people sampled, 480 had kids.

Q: Out of 400 people sampled, 68 had kids. Based on this, construct a 99% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the number of people sampled. From the…

Q: Out of 100 people sampled, 35 had kids. Based on this, construct a 95% confidence interval for the…

Q: Out of 300 people sampled, 228 had kids. Based on this, construct a 90% confidence interval for the…

A: Introduction Sample size, n=300 No. of people who had kids, x=228 CL=0.90

Q: A poll of 1785 U.S. adults found that 900 U.S. adults, or 50.42% regularly used Facebook as a news…

A: Given that: Sample proportion, p^=0.5042 sample size (n) =900

Q: Out of 600 people sampled, 462 had kids. Based on this, construct a 95% confidence interval for the…

A: We have given thatn = 600x = 462p̂ = x/n = 462/600 = 0.770Significance level (α) = 1 - 0.95 =…

Q: Out of 400 people sampled, 164 had kids. Based on this, construct a 95% confidence interval for the…

A: Given:Sample size = n = 400 peoplePeople having kids = x = 164Confidence level = 0.95So, α = 1 –…

Q: In a sample of 310 adults, 177 had children. Construct a 87% confidence interval for the true…

A: Find z-critical value:…

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

Q: Out of 500 people sampled, 455 had kids. Based on this, construct a 90 % confidence interval for the…

A: The formula for the confidence interval for the proportion is,

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: The sample size is 1072, 67% say they are willing to get a second or part-time job to pay for their…

Q: Out of 200 people sampled, 166 had kids. Based on this, construct a 90% confidence interval for the…

Q: To assess the proportion of the readers of a magazine being professional, a random sample of 1000…

A: Given that the random sample of 1000 readers is selected and 660 are found to be professionals. That…

Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

Q: Out of 500 people sampled, 330 had kids. Based on this, construct a 90% confidence interval for the…

Q: Out of 500 people sampled, 245 had kids. Based on this, construct a 95% confidence interval for the…

A: From the provided information, Out of 500 people sampled, 245 had kids. That is x = 245 and n = 500…

Q: Out of 600 people sampled, 240 have shopped online. Based on this, construct a 90% confidence…

A: Find z-critical value:…

Q: Out of 400 people sampled, 220 had kids. Based on this, construct a 99% confidence interval for the…

A: The random variable X follows binomial distribution. X ~ B (n, p) The sample size is 400. The number…

Q: A survey showed 980 of 1500 adult respondents believe in global warming. Construct a 95% confidence…

Q: Out of 600 people sampled, 228 had kids. Based on this, construct a 90% confidence interval for the…

Q: Out of 100 people sampled, 54 had kids. Based on this, construct a 90 % confidence interval for the…

Q: Out of 400 people sampled, 76 had kids. Based on this, construct a 90% confidence interval for the…

A: Find z-critical value:…

Q: Out of 600 people sampled, 180 had kids. Based on this, construct a 95% confidence interval for the…

A: The sample of 600 people is considered out of which 180 have a kid n=600x=312The 95% confidence…

Q: Out of 200 people sampled, 112 had kids. Based on this, construct a 95% confidence interval for the…

Q: Out of 100 people sampled, 27 had kids. Based on this, construct a 95% confidence interval for the…

Q: Out of 300 people sampled, 135 received flu vaccinations this year. Based on this, construct a 95%…

A: According to the given information, we haveTotal number of people sampled = 300135 received flu…

Q: Out of 600 people sampled, 510 had kids. Based on this, construct a 90% confidence interval for the…

A: It is given that Out of 600 people sampled, 510 had kids.

Q: Out of 200 people sampled, 50 had kids. Based on this, construct a 90% confidence interval for the…

A: Given that, Total number of people sampled = 200 Number of people had kids = 50 Confidence level =…

Q: Out of 300 people sampled, 282 had kids. Based on this, construct a 95% confidence interval for the…

Question

Out of 100 people sampled, 48 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids.

Give your answers as decimals, to three places

< p <

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

In a sample of 580 adults, 348 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places
Out of 100 people sampled, 82 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places.
Out of 100 people sampled, 34 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places
A poll of 1070 U.S. adults found that 563 U.S. adults, or 52.617% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Express all answers as percentages rounded to 2 decimal places. Do not write the percent sign. Margin of Error (as a percentage): Confidence Interval: Margin of Error (as a percentage): Confidence Interval: Now find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Margin of Error (as a percentage): Confidence Interval: % to O increases O stays roughly the same O decreases % to Finally, find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. and the precision of our estimate O decreases O increases O stays roughly the…
The owner of the Gas station wishes to determine the proportion of customers who use credit card. he surveys 100 customers and finds that 70 paid at the pump. Estimate the 99% .confidence interval for the population proportion
Out of 200 people sampled, 116 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to four places
Out of 200 people sampled, 84 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to three places < p <
Out of 600 people sampled , 102 had kids. Based on this , construct a 90% confidence interval for true population proportion of people with kids . give your answers as decimals to three places
Out of 400 people sampled, 368 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to four places< p <
Out of 200 people sampled, 76 had kids. Based on this, construct a 90% confidence interval for the truepopulation proportion of people with kids.Give your answers as decimals, to three places
Out of 200 people sampled, 170 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to four places < p <
Out of 100 people sampled, 40 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids.