Part 1 ( Where should we start? Notice that for the CH₂COOH, we know both the molarity and the volume. Since we know both the molarity and the volume, we can calculate moles: log, cos. 8. 15.00 ml CH₂COOH Part 2 XX IL 1000 ml. + Then, we can use the mole ratio to relate moles of CH₂COOH to moles of NaHCO₂: hog 0.126 mol CH₂COOH IL com A mol CH₂COOH A mol Nallo 0.00189 mol CH₂COOH Imol CH₂COOH mol NaHCO,

Part 1 ( Where should we start? Notice that for the CH₂COOH, we know both the molarity and the volume. Since we know both the molarity and the volume, we can calculate moles: log, cos. 8. 15.00 ml CH₂COOH Part 2 XX IL 1000 ml. + Then, we can use the mole ratio to relate moles of CH₂COOH to moles of NaHCO₂: hog 0.126 mol CH₂COOH IL com A mol CH₂COOH A mol Nallo 0.00189 mol CH₂COOH Imol CH₂COOH mol NaHCO,

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter4: Types Of Chemical Reactions And Solution Stoichiometry

Section: Chapter Questions

Problem 4RQ: Molarity is a conversion factor relating moles of solute in solution to the volume of the solution....

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