Points A and B have position vectors a = 2i + 3j – 4k and b = 2i – j + 2k. Point C has position vector c = 2i + (1 + 3t)j +(-1+ 2t)k. a Find in terms of t: i CẢ ii CB b Find the values of t for which ZBCA = 90°.

Trigonometry (MindTap Course List)
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ISBN:9781337278461
Author:Ron Larson
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Chapter3: Additional Topics In Trigonometry
Section3.3: Vectors In The Plane
Problem 10ECP
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Points A and B have position vectors a = 2i + 3j – 4k and b = 2i – j+ 2k. Point C has
position vector c = 2i + (1 + 3t)j +(-1+2t)k.
a Find in terms of t:
i CẢ
ii CB
b Find the values of t for which ZBCA = 90°.
Transcribed Image Text:Points A and B have position vectors a = 2i + 3j – 4k and b = 2i – j+ 2k. Point C has position vector c = 2i + (1 + 3t)j +(-1+2t)k. a Find in terms of t: i CẢ ii CB b Find the values of t for which ZBCA = 90°.
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