Points A and B have position vectors a = 2i + 3j – 4k and b = 2i – j + 2k. Point C has position vector c = 2i + (1 + 3t)j +(-1+ 2t)k. a Find in terms of t: i CẢ ii CB b Find the values of t for which ZBCA = 90°.
Points A and B have position vectors a = 2i + 3j – 4k and b = 2i – j + 2k. Point C has position vector c = 2i + (1 + 3t)j +(-1+ 2t)k. a Find in terms of t: i CẢ ii CB b Find the values of t for which ZBCA = 90°.
Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter3: Additional Topics In Trigonometry
Section3.3: Vectors In The Plane
Problem 10ECP
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