Problem 3B (harder) In this version, assume the two input strings can be of same or different lengths. For example, "apple Vs. ave s "base" vs. "basement". Same as above, this function starts by comparing the first character of each string. If they are equal, it continues with the following pairs until the characters differ, or, we reach the end of one of the stings (or reach both ends if the ngs nave the same length). If no mismatch is detected when one string is exhausted, for example, "base" vs. asement", then the shorter string is deemed lexicographically preceding the longer one, i.e., "base" <"basement", which means "base" should appear earlier in dictionary than "basement" (make sense, right) More examples, Expected output "abacus < boạt" "abacus > Boat" First input string Second input string "boat" "abacus" "abacus" "Boat" "building > beat" "apple > abut" "building" "beat" "apples" "еxam" "abut" "examines" "exam < examines" "apples > apple" "apples" "аpple" "apple" "apple" "apple == apple" Develop flowchart for this algorithm, Hint: first find the shorter length, and loop through only that range. Should stop loop immediately when a mismatch is found. But you cannot say, "go out of loop". Use the approach mentioned in class and lab to stop a loop earlier. The loop should only have one exit point. Save the flowchart as img_03B.jpg Implement this using JavaScript Use prompt to ask users for two strings For characters comparisons, just use < >=, as numerical values You should stop loop immediately when a mismatch is found. But cannot use break. Use the approach mentioned in class and use in labs to stop a loop earlier. The loop should only have one exit point.
Problem 3B (harder) In this version, assume the two input strings can be of same or different lengths. For example, "apple Vs. ave s "base" vs. "basement". Same as above, this function starts by comparing the first character of each string. If they are equal, it continues with the following pairs until the characters differ, or, we reach the end of one of the stings (or reach both ends if the ngs nave the same length). If no mismatch is detected when one string is exhausted, for example, "base" vs. asement", then the shorter string is deemed lexicographically preceding the longer one, i.e., "base" <"basement", which means "base" should appear earlier in dictionary than "basement" (make sense, right) More examples, Expected output "abacus < boạt" "abacus > Boat" First input string Second input string "boat" "abacus" "abacus" "Boat" "building > beat" "apple > abut" "building" "beat" "apples" "еxam" "abut" "examines" "exam < examines" "apples > apple" "apples" "аpple" "apple" "apple" "apple == apple" Develop flowchart for this algorithm, Hint: first find the shorter length, and loop through only that range. Should stop loop immediately when a mismatch is found. But you cannot say, "go out of loop". Use the approach mentioned in class and lab to stop a loop earlier. The loop should only have one exit point. Save the flowchart as img_03B.jpg Implement this using JavaScript Use prompt to ask users for two strings For characters comparisons, just use < >=, as numerical values You should stop loop immediately when a mismatch is found. But cannot use break. Use the approach mentioned in class and use in labs to stop a loop earlier. The loop should only have one exit point.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Transcribed Image Text:the following pairs until the characters differ, or, we reach the end of one of the stings (or reach both ends if the
Same as above, this function starts by comparing the first character of each string. If they are equal, it continues with
Problem 3B (harder)
m his version, assume the two input strings can be of same or different lengths. For example, "apple Vs. dve
"base" vs. "basement".
he following pairs until the characters differ, or, we reach the end of one of the stings (or reach both ends l uhe
"Lo nave the same length). If no mismatch is detected when one string is exhausted, for example, "base" Vs.
basement", then the shorter string is deemed lexicographically preceding the longer one, i.e., "base" < "basement ,
which means "base" should appear earlier in dictionary than "basement" (make sense, right)
More examples,
Expected output
"abacus < boat"
First input string
Second input string
"abacus"
"boat"
"abacus"
"Boat"
"abacus > Boat"
"building"
"beat"
"building > beat"
"apple > abut"
"exam < examines"
"abut"
"apples"
"exam"
"examines"
"apples"
"аpple"
"apple"
"apple"
"apples > apple"
"apple
apple"
Develop flowchart for this algorithm,
Hint: first find the shorter length, and loop through only that
Should stop loop immediately when a mismatch is found. But you cannot say, "go out of
loop". Use the approach mentioned in class and lab to stop a loop earlier. The loop should
only have one exit point.
Save the flowchart as img_03B.jpg
range.
Implement this using JavaScript
Use prompt to ask users for two strings
For characters comparisons, just use < >==, as numerical values
You should stop loop immediately when a mismatch is found. But cannot use break. Use the
approach mentioned in class and use in labs to stop a loop earlier. The loop should only have
one exit point.
![Sample input /output
apple
ape
problem1A -- array sort
problem18- aray sort [in-place]
problemB - aray search
problem3A -- string compare [sarne length]
problem38 - string compare](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdac761a6-ba1c-4b50-93cd-f82ea0746880%2F10c46fe2-7c6d-44f0-a252-d70fe472b987%2F11saehd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Sample input /output
apple
ape
problem1A -- array sort
problem18- aray sort [in-place]
problemB - aray search
problem3A -- string compare [sarne length]
problem38 - string compare
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