proton enters a parallel plate system moving with an initial velocity of 9413.1 m/s perpendicular to the electric field. The proton enters at the the positive plate and the electric field between the plates moves it in the direction of the negative plate. The plate separation distance is 19.2 cm and the potential difference between the plates is 1.9 V. What is the magnitude of the final velocity of the proton when it hits the negative plate? ( Please state what kinematics formula was used to find final velocity through the steps.)
proton enters a parallel plate system moving with an initial velocity of 9413.1 m/s perpendicular to the electric field. The proton enters at the the positive plate and the electric field between the plates moves it in the direction of the negative plate. The plate separation distance is 19.2 cm and the potential difference between the plates is 1.9 V. What is the magnitude of the final velocity of the proton when it hits the negative plate? ( Please state what kinematics formula was used to find final velocity through the steps.)
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 3OQ: A proton is released from rest at the origin in a uniform electric field in the positive x direction...
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A proton enters a parallel plate system moving with an initial velocity of 9413.1 m/s perpendicular to the electric field. The proton enters at the the positive plate and the electric field between the plates moves it in the direction of the negative plate. The plate separation distance is 19.2 cm and the potential difference between the plates is 1.9 V. What is the magnitude of the final velocity of the proton when it hits the negative plate? ( Please state what
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