Q5. For the following center tapped transformer, show the waveform across each half of the secondary winding and across Ri, when a 100 V peak sine wave is applied to the primarywinding. What is the PIV rating must the diode have? (Use constant voltage drop model for the Silicon diode)
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- What is the difference between a diode and rectifier?0:- Consider the circuit in Figure a) What type of circuit is this? b) Find and Sketch the voltage waveform across RL, assume the diodes are practical. c) If 100uf capacitor parallel with the resistor, calculate the ripple is connected factor I O o DIn the circuit shown below. Determine the following a. Vs (at the secondary) b. Vout (across RL) c. Vrip (ripple votage) d. VDC e. PIV (Peak Inverse Voltage) 10:1 Output 115 V mis 60 Hz RL 2.2 k) D, 50μF- All diodes are IN4001. Tund AlMannai EENG261 Page 5/11
- A full-wave rectifier uses 2 diodes. The internal resistance of each diode is 20 Q. The transformer RMS secondary voltage from centre tap to each end of the secondary is 50 V and the load resistance is 980 Q. Mean load current will beDraw vx and v0 according to the input voltages in the circuit shown in the figure. note = R1 = 10Kohm R2 = 1kohm R3 = 1Kohm, the threshold voltages of diodes will be VE = 0.7V.Problem # 4 In the circuit shown below. Determine the following a. Vs (at the secondary) b. Vout (across RL) c. Vrip (ripple votage) d. VpC e. PIV (Peak Inverse Voltage) 10:1 Dy 1ISV ms Ouiput RL 2.2 k2 D, 50 pF All diodes are IN4001. alleee
- consider the figure below that shows an approximated reverse recovery turn-off characteristics for a power diode. Show that the following relation can express the total reverse recovery charge, Qrr = 1/2(trr*ts1) di1/dt =1/2(trr*ts21) di2/dt * ip Isl 1s2! -Ir3 Given the bridge-type full-wave rectifier circuit shown 220V 60Hz 220V:Es Es D1 D2 D3 D4 The load resistor is 220 and the transformer average current is 300mA. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Average current and PIV of each diode. RLDraw the input waveform and output waveform for the circuit given below with proper values marked in the figure. Assume D1 as silicon and D2 as germanium diodes. Input Vpp=20V. V1=5 V and V2=9 V. R www D1 Vin Vout v1 V2 Maximum voltage of output waveform Minimum voltage of output waveform
- A full wave bridge rectifier is supplied from 230V, 50Hz and uses a transformer of turns ration 15:1. It uses load resistance of 50 ohms. Calculate load voltage and ripple voltage. Assume ideal diode and transformer. Assume ripple factor equals to 0.482. a.Load Voltage= 13.8 V; Ripple Voltage=6.652 V b.Load Voltage= 15.6 V; Ripple Voltage=7.611 V c.Load Voltage= 21.3 V; Ripple Voltage=8.410 V d.Load Voltage= 25.1 V; Ripple Voltage=10.442 VPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20VQ5. For the following center tapped transformer, show the wave form across each half of the secondary winding and across R1, when a 100 V peak sine wave is applied to the primarywinding. What is the PIV rating must the diode have? (Use constant voltage drop model for the Silicon diode) IN4001 R 10 ΚΩ I14001 Q6. Can we operate normal PN junction diode in breakdown region for longer duration? Give reason Q7. What is the specialty of Zener diode so as we can operate it in breakdown region for longer duration? Q8. What is the difference between Zener breakdown and Avalanche breakdown? Q9. Draw Zener regulator circuit to obtain regulated DC voltage 6.8 V. Considering input DC voltage in the range from 10V to 30V. Consider load resistance of 10KS. Q10. Determine maximum and minimum value of Zener current if value of series resistance is 1 K, load resistance is 2KN and input varies from 10V to 30V. Zener voltage is 5 V. Q11. What is LED? Q12. Which materials are used in manufacturing of LEDS?…