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- Consider the following segment table:Segment Base Length Base Limit0 1200 5001 2200 10242 6400 2563 8000 700What are the physical addresses for the following logical addresses?a. 2, 250b. 3, 690c. 0, 515Consider the following segment table: Segment Segment (Base) Length (Limit) 0 319 560 1 3200 14 2 89 95 3 1330 600 What are the physical addresses for the following logical addresses? Segment Offset a 0 430 b 1 10 c 2 500 d 3 400Check the following schedules, whether they are conflict serializable? S1: R1(X); W1(X); R2(X); R1(Y); W1(Y); R2(Y) S2: R1(X); W1(X); R2(X); R2(Y); R1(Y); W1(Y)
- Q) An ISP is granted a block of addresses starting with 150.80.0.0/16. The ISP wants to distribute these blocks to 2600 customers as follows; a) The first group has 200 medium-size businesses; each needs 128 addresses.b) The second group has 400 small businesses; each needs 16 addresses.c) The third group has 2000 households; each needs 4 addresses. Design the sub-blocks and give the slash notation for each sub-block. Find out how many addresses are still available after these allocations.Briefly explain extended destination indexIn the RENTALS table shown in fig 2, 40 customers have created 50 rental contracts over time. A RENTALS record is 122 bytes and the block size for your OS is set to 1024 bytes with each block having a 1 byte pointer to the next written block as well as a 1 byte pointer to the next physically consecutive block. Calculate the blocking factor for unspanned blocking of RENTALS records. a)4 b)400 c)320 d)8
- Consider the following segment table: What are the physical address for the following logical address? a) 0,826 b) 1,269 c) 2,8 d) 3,700 e) 4,138 Segment Base (Starting Address) Length (bytes) 0 103 529 1 20 264 2 909 9 3 1974 980 4 7929 176Consider the following segment table (all expressed and addressed in bytes) Segment Base Length 0 500 1000 1 4500 1500 2 7000 3000 3 11000 2400 4 15000 875 What are the physical addresses for the following logical addresses? a. 0,430 b. 1,1520 c. 2,500 d. 3,400 e. 4,1120Determine the first 4 subnets and usable address range of the following and submit your table on Canvas. 192.168.200.0/24 for 58 addresses 172.16.10.0/24 for 28 addresses 10.10.10.0/24 for 100 addresses 209.165.200.0/24 for 10 addresses
- An ISP is granted a block of addresses starting with 129.80.0.0/16. The ISP wants to distribute these blocks to 2600 groups as follows: i. The first group has 200 medium sized businesses; each needs 14 hosts. ii. The second group has 400 small businesses; each needs 6 hosts. iii. The third group has 2000 point-to-point links; each needs 2 hosts. iv. Design the sub-blocks and give the slash notation for each sub-blockAn ISP is granted a block of addresses starting with 10.100.10.0/16.The ISP needs to distribute these addresses to three groups ofcustomers as follows:. The first group has 64 customers; each needs 128 addresses.. The second group has 128 customers; each needs 128 addresses.. The third group has 128 customers; each needs 32 addresses.. Design the sub blocks and find out how many addresses are still available after these allocation.How are logical and linear addresses related to one another, and what are their differences?