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- Q1: Write a C# program that finds the value of Y from the following series: X xn x² x3 + 3! 5! 7! + (2n+1)! Note: while statement for outer loop and for statement for inner loops must be used. Don't use class, or functions Y= 1 + -(Numerical) Write a program that tests the effectiveness of the rand() library function. Start by initializing 10 counters to 0, and then generate a large number of pseudorandom integers between 0 and 9. Each time a 0 occurs, increment the variable you have designated as the zero counter; when a 1 occurs, increment the counter variable that’s keeping count of the 1s that occur; and so on. Finally, display the number of 0s, 1s, 2s, and so on that occurred and the percentage of the time they occurred.CODE USING C++ 3. Place Values by CodeChum Admin Manipulating values from a series of numbers is fun, but let's try exploring the use of loops a little more. How about printing out each digit of a number by place values, in ascending order? Instructions: Create a variable and input a random positive integer. Using while loop, print out each digit of the inputted integer in separate lines, starting from its rightmost digit until the leftmost digit of the number. Tip: Use % 10 to get the rightmost digit, and / 10 to remove it from the number. Another tip: don't forget to consider the case wherein the input is `0` Input A line containing an integer. 214 Output Multiple lines containing an integer. 4 1 2
- In C++ (Algebra: solve 2 × 2 linear equations) You can use Cramer’s rule to solve the following 2 × 2 system of linear equation: ax + by = ecx + dy = fx = (ed - bf) / (ad - bc)y = (af - ec) / (ad - bc) Write a program that prompts the user to enter a, b, c, d, e and f and displays the result. If ad - bc is 0, report that “The equation has no solution”. Sample Run 1 Enter a, b, c, d, e, f: 9.0 4.0 3.0 -5.0 -6.0 -21.0 x is -2 and y is 3 Sample Run 2 Enter a, b, c, d, e, f: 1.0 2.0 2.0 4.0 4.0 5.0 The equation has no solution*Modify the program so that the user will error trap for only 1 and 0 as an input. *If the user enters an input other than 1 or 0 display an error message and request the user enter that input again. *Do this for all inputs in the code. # User defined function for logic OR# The function takes two parameters and returns a single intdef OR(a: int, b: int)->int:# If a is equal to 1 return 1if a == 1 :return 1# If b is equal to 1 return 1elif b == 1 :return 1# If a and b is equal to 0 return 0else :return 0 # User defined function for logic NOR# The function takes two parameters and returns a single intdef NOR(a: int, b: int)->int:# If a is equal to 0 and b is also equal to 0 return 1if a == 0 and b == 0 :return 1# If a is equal to 0 and b is equal to 1 return 0elif a == 0 and b == 1 :return 0# If a is equal to 1 and b is also equal to 0 return 0elif a == 1 and b == 0 :return 0# If a is equal to 1 and b is also equal to 1 return 0elif a == 1 and b == 1 :return 0 # User defined…Language: C++ (Apartment problem) A real estate office handles , say, 50 apartment units. When the rent is, say, $600 per month, all the units are occupied. However, for each, say $40 increase in rent, one unit becomes vacant. Moreover, each occupied unit requires an average of $27 per month for maintenance. How many units should be rented to maximize the profit? Write a program that prompts the user to enter: The total number of units. The rent to occupy all the units. The increase in rent that results in a vacant unit. Amount to maintain rented unit. The program then outputs the number of units to be rented to maximize the profit. Note: Please include the pseudocode
- Q1: Write a C# program that finds the value of Y from the following series: x5 x7 x2n+1 Y= x³ + + 2! 3! n! Note: for statement for outer loop and while statement for inner loops must be used. Note2: Do not use classes or functions to solve this questionC++ Demonstration: Write a program that computes the equivalent resistance of a purely series and purely parallel electric circuit. TEST CASES: If the user inputs a character: Computing for the equivalent resistance A. Series CombinationB. Parallel Combination Enter Choice: B Enter R1: 1 Enter R2: 2 Enter R3: A The value of R3 is not a number. If the user selects “Series Combination” and inputs numbers: Computing for the equivalent resistance A. Series Combination B. Parallel Combination Enter Choice: A Enter R1: 1 Enter R2: 2 Enter R3: 3 The total resistance in series is 6 Ohms.In C++ Language: (Check password) Some websites impose certain rules for passwords. Suppose the password rules are as follows: - A password must have at least eight characters. - A password must consist of only letters and digits. - A password must contain at least two digits. Write a program that prompts the user to enter a password and displays valid password if the rules are followed or invalid password otherwise.
- Note:solution using c++ language Pre-Lab 01: Write a program that reads a positive integer x from the user. If x is even, the program prints all the odd numbers between 1 and x – inclusive - each on a separate line. If x is not even, the program prints all the numbers that are multiples of 4 between 1 and x+10 -inclusive -, each on a separate line. Note: As long as the user does not enter a positive number, the program will repeatedly ask the user to enter a positive number. The program must also print an error message "Error- TRY AGAIN – You should enter a positive integer to continue". Úe do.. while to insure the user input.Change this code into a program that receives a number and prints its divisors.( C language) #include <stdio.h> int main() { unsigned guess; /* current guess for prime */ unsigned factor; /* possible factor of guess */ unsigned limit; /* find primes up to this value */ printf("Find primes up to: "); scanf("%u", &limit); printf("2\n"); /* treat first two primes as special case */ printf("3\n"); guess = 5; /* initial guess */ while ( guess <= limit ) { /* look for a factor of guess */ factor = 3; while ( factor*factor < guess && guess % factor != 0 ) factor += 2;if ( guess % factor != 0 ) printf("%d\n", guess); guess += 2; /* only look at odd numbers */ } return 0; }void change( int a[]) , the compiler converts the parameter to: Select one: a. int *const a b. int &a; c. int a d. const int a; c++