Question 1What is the Big-O running time of the following section of code?for i = 1 to nfor j = n downto 1print ("This step takes constant time per execution.")foTAA%Use the editor to format your answerBIUWord count: 0***YE. TQuestion 2What is the Big-O running time of the following section of code?for i = 1 to n▾for j = 1 to iprint ("This step takes constant time per execution.")

Time complexity is a measure of the amount of time an algorithm takes to run as a function of the…

Answered: Question 1 What is the Big-O running…

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter14: Exception Handling

Section: Chapter Questions

Problem 10SA

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Let Z1Z2Z3Z4 be the last four digits of you student ID. • Let RO=0x0000 Z1Z2Z3Z4, R1=0x0000 4500 and R15=0x0011 2233, when the code below is run. CMP R1, RO BHS XYZW ADD R1,R1,# Ox10 XYZW ADD RO,RO,# 0x01 What are the contents of RO, R1 and R15 after this code runs?
Use the Bash shell for the completion of this project.Develop a shell scripting application that allows the user to perform some advanced mathematicaloperations: Task 3: Find the numbers that can be expressed as the product of two nonnegative integers in succession and print them in increasing order. For each number found the program should check whether the number is a multiple of 5 and indicate this in the output. (For example, 30 is such anumber as it can be written as the product of 5 and 6 (30=5x6), which are two numbers in succession.) The user should specify how many such numbers they want to print.
Consider the following code snippet, which uses the AddThree procedure defined below: .data sum BYTE ? .code mov eax, 11 mov edx, 10 mov esi, 1 call AddThree mov sum, eax AddThree PROC push edx push esi add edx, esi add eax, edx pop esi pop edx ret AddThree ENDP Which of the following are the arguments (input parameters) for this procedure? (Select all that apply) edx sum eax O esi
PYTHON QUESTION : The Syracuse sequence of an integer N is the sequence of integers starting with the term N, where each following term is half of the preceding term if it is even, and one plus three times the preceding term if it is odd. The sequence ends when it reaches the integer 1. The maximum of the Syracuse sequence of an integer N is the highest number reached by this sequence. This maximum can sometimes be very high compared to the starting integer N. What is the maximum of the Syracuse sequence of 3428767? To answer this question it is useful to modify the code given in demonstration which calculates the Syracuse sequence. The code given in the demo : n = 27 print(n) while n != 1: if n%2 == 0: n = n // 2 # where n //= 2 or n >>= 1 else: n = 1 + 3*n print(n)
Give the result of the following code: quotaThis Month = 7 quotaLastMonth = quotaThis Month + 1 if (quotaThis Month > quota LastMonth) or \ (quotaLastMonth >= :8): print("Yes") quotaLastMonth = quotaLastMonth + 1 else: print("No") quotaThis Month = quotaThis Month Blank 1 Blank 1 Add your answer
What will be the value in AX after the execution of the following code? MOV AX, 1000H MOV DX, 1000H MOV BX, 1000H DIV BX
def cuberoot(n): """Computes the cube root of float n by fixpoint iteration""" cuberoot: This function should use fixed-point iteration to return the cube root of a given n (positive or negative floating point number). Your implementation should ideally return a precise approximation, but must be correct to at least eight significant digits and must use fixpoint iteration.
Hello there: I must follow the below instructions very carefully to complete the code. My code is not working. Can you help me to fix it? In the def reverse function, I'm stuck there with the instructions. Thanks in advanced! The instructions are in the code comments. Also, you can see some output examples. import numpy as np # SIZE is a global constant, use this throughout your program. # you should be able to change this to any int and your # whole program will still work correctly. TEST THIS! SIZE = 10 STATS_SIZE = 4 MULTIPLIER = 10 # initialize the array with 10, 20, 30, etc. def make_array(): # creates a numpy array of size SIZE filled with 0s. nums = np.array([0] * SIZE, dtype=int) # now fill it with 10,20,30, etc ***using a loop*** and return it def calc_stats(nums): stats = np.array([0] * STATS_SIZE, dtype = int) stats[0] = np.min(nums) stats[1] = np.max(nums) stats[2] = np.sum(nums) stats[3] = int(np.mean(nums)) # make an integer array of size 4 to…
Please note that on the last line of the code, we need to print out the 'and" with the smallest and the largest number for min and max functions in order to maximize our credit with the zyBooks lab assignment for 3.9. Code Hints: smallestnum = min(usernumbers) #The smallest number is printed out - for example 5, 10, 15 - 5 would be printed out largestnum = max(usernumbers) #The largest number is printed out - for example 5, 10, 15 - 15 would be printed out Write a program that reads a list of integers into a list as long as the integers are greater than zero, then outputs the list values and the smallest and largest integers in the list using min and max built-in functions . Ex: If the input is: 10 5 3 21 2 -6 the output is: [10, 5, 3, 21, 2] 2 and 21 user_numbers = [] user_input = int(input())while user_input > 0: user_numbers.append(user_input) user_input = int(input())print(user_numbers) ''' Complete code here. '''smallest_num=min(user_numbers)largest_num =…
Please note that on the last line of the code, we need to print out the 'and" with the smallest and the largest number for min and max functions in order to maximize our credit with the zyBooks lab assignment for 3.9. Code Hints: smallestnum = min(usernumbers) #The smallest number is printed out - for example 5, 10, 15 - 5 would be printed out largestnum = max(usernumbers) #The largest number is printed out - for example 5, 10, 15 - 15 would be printed out Write a program that reads a list of integers into a list as long as the integers are greater than zero, then outputs the list values and the smallest and largest integers in the list using min and max built-in functions . This code runs in zyBooks..... Ex: If the input is: 10 5 3 21 2 -6 the output is: [10, 5, 3, 21, 2] 2 and 21 user_numbers = [] user_input = int(input())while user_input > 0: user_numbers.append(user_input) user_input = int(input())print(user_numbers) ''' Complete code here.…
The following code plots the ground coverage of an satellite orbiting the earth. Can you give me the code to figure out how much time does the building have coverage from the satellite everyday? Please make sure the code gives a reasonable answer % At the initial time, the true anomaly is equal to zero,% and the Greenwich meridian points to the Aries point. % Initial conditionsomega_earth = rad2deg(7.2921151467e-5); % deg/ssemi_major_axis = 3096.7363; % kmeccentricity = 0.74;inclination = 63.4349; % degreesRAAN = -86.915798; % degreesargument_of_perigee = 270; % degreesn_points = 100; % number of pointscone_angle = 10; % degrees % Building coordinatesbuilding_latitude = 40.43094; % degreesbuilding_longitude = -86.915798; % degrees % Calculate time vector over one orbital periodorbital_period = 360 / omega_earth;time_vector = linspace(0, orbital_period, n_points); % Preallocate arrays for orbital elementstrue_anomaly = zeros(1, n_points);longitude = zeros(1, n_points);latitude =…
PYTHON In the following cell, complete the code so that N is returned when the difference between shortcut_formula(C,r) and summation_formula(C,r,N) is less than 0.010.01. Hint: the solution to this question needs only two lines of code. It will look something like: if <condition>: return N def good_enough(C,r):Return the smallest value of N that satisfies true_value - estimated_value < 0.01for N in range(1000):true_value = shortcut_formula(C,r)estimated_value = summation_formula(C,r,N)return -1

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