Question 5: 2.1 Sum Problem View Past Answers Given a positive number n, the sum of all digits is obtained by adding the digit one-by-one. For example, the sum of 52634 is 5+2+6+3+4 = 20. Write a recursive and iterative function sum(n) to compute the sum of all the digits in n. You may assume that n > 0. template.py 1- def sum R(n): if len(str(n)) == 1: return n else: return 20 7. def sum I(n): add = 0 while n: add += n % 10 8 9- 10 n //= 10 return add 11 12

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
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Question 5: 2.1 Sum Problem
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Given a positive number n, the sum of all digits is obtained by adding the digit one-by-one. For example, the sum of 52634 is 5+ 2 +6 +3 + 4 = 20. Write a recursive and iterative function
sum (n) to compute the sum of all the digits in n. You may assume that n > 0.
template.py
1 def sum R(n):
if len(str(n)) == 1:
2-
return n
else:
return 20
7. def sum_I(n):
add = 0
8
while n:
10
add += n % 10
n //= 10
return add
11
12
Transcribed Image Text:Question 5: 2.1 Sum Problem View Past Answers Given a positive number n, the sum of all digits is obtained by adding the digit one-by-one. For example, the sum of 52634 is 5+ 2 +6 +3 + 4 = 20. Write a recursive and iterative function sum (n) to compute the sum of all the digits in n. You may assume that n > 0. template.py 1 def sum R(n): if len(str(n)) == 1: 2- return n else: return 20 7. def sum_I(n): add = 0 8 while n: 10 add += n % 10 n //= 10 return add 11 12
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