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- Design Specifications 1st and 2nd floor Member Roof Deck Load (Typical) Live Load Item Superimposed Dead Load (Typical) Live Load Superimposed Dead a. b. C. For the structural plan attached, Hint: Self-weight B1 B2 Notes: 1. For simplicity, neglect self-weight of concrete slab B3 G1 G2 C1 C2 Design Loadings Application Slabs Slabs Slabs Slabs Value 4 3 2 3 4 4 4 Value 4 means pinned means continuous Assume all members have the same stiffness (same El) for simplicity 8 4 6 Unit kN/m kN/m kN/m kN/m kN/m kN/m kN/m Unit kPa kPa kPa kPa Determine the factored bending moment (LRFD) to be used in the design of Beam B1 in kNm. Determine the factored shear force (LRFD) to be used in the design of Girder G2 in kN. Determine the factored axial load (LRFD) to be used in the design of Column C1 in kN. -I T C2 G2 C1 G1 C1 5000 B3 1 B2 B1 B2 C2 C1 ∙H. GROUND FLOOR FRAMING PLAN C1 I G2 H G1 İ 8 C2 C1 G1 C1 5000 B3 1 B2 B1 + B2 1 B3 . C2 C1 I C1 SECOND FLOOR AND ROOF DECK FRAMING PLAN G1 G1The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec =23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m. f' = 25MPa 800 IDE 730 N12 ligs (fsv.f-500MPa) Ast = 3N28 350 Span = 10m Figure 3 Calculate the combination load for the reinforcement concrete beam shown in Figure 3. Unit: KN/m with two decimal. 1.2G+1.5Q=wAnswer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 in
- 3. A reinforced rectangular concrete beam having a width of 300 mm, effective depth of500 mm, fc’ = 24 MPa, fy = 415 MPa, 4 - 28 mmɸ, d’ = 65 mm. Present the following (a) actual steel ratio (b) maximum steel ratio (c) a(d) c (e) check if steel yields (f) ?steel(g) type of failure (h) reduction factor (i) moment capacity1. A steel column 10 m long is fabricated from a cover plate and C section arranged as shown. Determine the safe compressive load. Fy = 248 MPa, E= 200 GPa. Use AISC/NSCP Specs. 450 mm -cover plate 'I 12 mm y2 IP d2 10 m C 310 x 37 A = 4720 mm? d = 305 mm bf = 77 mm tf = 12.7 mm tw = 9.8 mm C 310 X 37 a) Both ends of column are fixed b) Both ends of column are hinged c) One end fixed, the other end hinged Use design values of k. tw d=305- Ix = 59.9x10° mm ly = 1.85x10° mm x = 17.1 mm x=17.1A rectangular beam 250 mm wide, 500 mm deep is reinforced at the bottom with d-20-mm-dismeter bars and at the top with 2-16-mm bars. Concrete cover to bar centroid at the top is M0 mm and at the bottom is 70 mm. Use concrete strength r'e-21 MPa und steel yield strength fy 415 MPa for 20- mm bars and fy= 275 MPA for 16 mm bars Detenmine the design moment capacity n kN m of the beam in negative bending. A 40.06 O45.07 C. 42.70 D47.55
- Details of a rectangular column are as follows: Column width along X-axis-250 mm Column Depth along the Y-axis-600 mm 8-25 mm diameter bars distributed equally along the longer sides. 10 mm diameter ties spaced at 10 mm on centers Concrete 28th day Compressive strength, fc;=20.7 MPa Reinforcing Steel yield strength, fy-415 MPa Assume that compression steel yields. a) Which of the following gives the nominal balanced load Pb (kN). A = 90.4 mm b) Which of the following gives the nominal axial load (kN) that the column n carry at an eccentricity of 200 mm along the X axis from the centroidal Y-axis.USE NSCP 2010 A simply supported beam is reinforced with 4 – 28 mm ø at the bottomand 2 – 28 mm ø at the top of the beam. Steel covering to centroid ofreinforcement is 70 mm at the top and bottom of the beam. The beamhas a total depth of 400 mm and a widthof 300 mm. fc’ = 30 MPa, fy = 415 MPa. Balanced steel ratio ρb = 0.031.Compute the ultimate moment capacity of the beam in kN-m. Usereduction factor of 0.90Use 2015 NSCP. A compression member shown below with Fy = 50 ksi 30′ W12 x 87 A992 steel 1. Which of the following most nearly gives the value of critical buckling stress in ksi? 2. Which of the following most nearly gives the nominal strength in kips? 3. Considering ASD. Which of the following most nearly gives the allowable strength in kips? 4. Considering LRFD. Which of the following most nearly gives the design strength in kips?
- The below figure represents a section of a pre- stressed beam. For a no-tension design where a is the permissible stress in concrete, the total moment carrying capacity is (a) (c) d/2 bd² 6 d/2 bd²oc 3 -b- (b) (d) bd² oc 4 bd²a 12A prestressed T beam shown which is reinforced with a bonded tendon having an area Aps = 1580 mm?, fc' = 34.5 MPa, fpu = 1862 MPa, and the effective stress after losses fse = 1102 MPa, fpy= 1713 MPa. Span of the beam is 6 m. %3! 1220 mm 0.85 fc 804 C NA 600 d-a/2 Aps 60 T=Ape fps 250 Find the live load that can be carry by the beam using USD load combination if the concrete's specific gravity is 2.4. (kN/m)Design the most economical section for a single span beam which carries a uniform load of 10 kN/m and has an unsupported span of 4m using ASD. It is subjected to a compressive load of 200 kN at its centroid. The beam is fixed at both ends. Use Narig @ 63% Stress Grade. Use NSCP 2015 as reference.