SOLUTION Find the mass of the system from the 3.00 x 10² N = 30.6 kg m = definition of weight, w = mg. 9.80 m/s Find the acceleration of the system F a, = = 20.0 N 0.654 m/s? from the second law. m 30.6 kg Use kinematics to find the distance Ax = ½a,t? = V½(0.654 m/s²)(2.00 s)? = 1.31 m %3D moved in 2.00 s, with vo = 0. LEARN MORE REMARKS Note that the constant applied force of 20.0 N is assumed to act on the system at all times during its motion. If the force were removed at some instant, the system would continue to move with constant velocity and hence zero acceleration. The rollers have an effect that was neglected here. QUESTION If the weight of the crate were doubled, the acceleration would be multiplied by and the displacement attained in 2.0 s would be multiplied by 1/2 1/2 PRACTIĆE IT Use the worked example above to help you solve this problem. The combined weight of the crate and dolly as shown in the figure is 3.20 x 102 N. If the man pulls on the rope with a constant force of 19.0 N, what is the acceleration of the system (crate plus dolly), and how far will it move in 2.00 s? Assume that the system starts from rest and that there are no friction forces opposing the motion. acceleration m/s2 displacement

SOLUTION Find the mass of the system from the 3.00 x 10² N = 30.6 kg m = definition of weight, w = mg. 9.80 m/s Find the acceleration of the system F a, = = 20.0 N 0.654 m/s? from the second law. m 30.6 kg Use kinematics to find the distance Ax = ½a,t? = V½(0.654 m/s²)(2.00 s)? = 1.31 m %3D moved in 2.00 s, with vo = 0. LEARN MORE REMARKS Note that the constant applied force of 20.0 N is assumed to act on the system at all times during its motion. If the force were removed at some instant, the system would continue to move with constant velocity and hence zero acceleration. The rollers have an effect that was neglected here. QUESTION If the weight of the crate were doubled, the acceleration would be multiplied by and the displacement attained in 2.0 s would be multiplied by 1/2 1/2 PRACTIĆE IT Use the worked example above to help you solve this problem. The combined weight of the crate and dolly as shown in the figure is 3.20 x 102 N. If the man pulls on the rope with a constant force of 19.0 N, what is the acceleration of the system (crate plus dolly), and how far will it move in 2.00 s? Assume that the system starts from rest and that there are no friction forces opposing the motion. acceleration m/s2 displacement

Name: SOLUTIONFind the mass of the system from the3.00 x 10² Ndefinition of
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Description: SOLUTIONFind the mass of the system from the3.00 x 10² Ndefinition of weight, w = mg.m =9.80 m/s2= 30.6 kgFind the acceleration of the systemFa, = =20.0 N0.654 m/s?from the second law.m30.6 kgUse kinematics to find the distanceAx = ½a,t? = V½(0.654

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter5: Newton's Law Of Motion

Section: Chapter Questions

Problem 62P: Consider Figure 5.28. The driver attempts to get the car out of the mud by exerting a perpendicular...

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