Solution:- Given H(jw) -(4+jw) 6+5jw-w² It Can Yewrite as:- (jw+4) (- : j²= + 1) 6+ (jw)² + 5jw = (jas+ 4) (jw+3) (jw+ 2) -1 (jw+3) (jw12) How did he get the value inside the circle (o by partial fraction) we get, A=-1&

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