Solve the following system of equations using the Gauss elimination method 2x1 + x2 – x3 + 4x4 = 19 -x1 – 2x2 +X3 + 2x4 = -3 2x1 + 4x2 + 2x3 + x4 = 25 – 2x4 %3D -x1 + x2 – x3 – 2x4 = -5
Solve the following system of equations using the Gauss elimination method 2x1 + x2 – x3 + 4x4 = 19 -x1 – 2x2 +X3 + 2x4 = -3 2x1 + 4x2 + 2x3 + x4 = 25 – 2x4 %3D -x1 + x2 – x3 – 2x4 = -5
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.5: Multiplication With The Addition-or-subtraction Method
Problem 18WE
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![Solve the following system of equations using the Gauss elimination method
2x1 + x2 - X3 + 4x4
—х1 — 2х2 + хз + 2х4 — -3
2х1 + 4x2 + 2хз + X4 —D 25
= 19
—х1 + X2 — хз — 2x4 — —5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F97f2f86e-839d-4be4-8480-90dc707207d7%2Fc10fae6a-8410-406e-b37a-928edbe7d3c7%2Fetifks_processed.png&w=3840&q=75)
Transcribed Image Text:Solve the following system of equations using the Gauss elimination method
2x1 + x2 - X3 + 4x4
—х1 — 2х2 + хз + 2х4 — -3
2х1 + 4x2 + 2хз + X4 —D 25
= 19
—х1 + X2 — хз — 2x4 — —5
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