Some PCI5 is allowed to dissociate into PCI3 and Cl₂ at 523 K. At equilibrium, [PCI5] = 0.171 M, and [PCI3] = [Cl₂] = 9.24x10-2 M. Additional PCIs is added so that [PCI5]new = 0.314 M and the system is allowed to once again reach equilibrium. PCI5 (9) PC13 (9) + Cl₂(9) K = 5.01x10-2 at 523 K (a) In which direction will the reaction proceed to reach equilibrium? | (b) What are the new concentrations of reactants and products after the system reaches equilibrium? [PCI5] = M [PCI3] = M [Cl₂] M

Chemistry for Engineering Students
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.40PAE: Because carbonic acid undergoes a second ionization, the student in Exercise 12.39 is concerned that...
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Tutored Practice Problem 15.4.1 COUNTS TOWARDS GRADE
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Predict and calculate the effect of concentration changes on an equilibrium system.
Some PCI5 is allowed to dissociate into PCI3 and Cl₂ at 523 K. At equilibrium, [PCI5] = 0.171 M,
and [PCI3] [Cl₂] = 9.24x10-2 M. Additional PCIs is added so that [PCI5]new = 0.314 M and
=
the system is allowed to once again reach equilibrium.
PCI5 (9) =PC13(9) + Cl₂(9) K = 5.01x10-2 at 523 K
(a) In which direction will the reaction proceed to reach equilibrium? |
(b) What are the new concentrations of reactants and products after the system reaches
equilibrium?
[PCI5] =
M
[PCI3] =
M
[Cl₂] =
M
Transcribed Image Text:Tutored Practice Problem 15.4.1 COUNTS TOWARDS GRADE Close Problem Predict and calculate the effect of concentration changes on an equilibrium system. Some PCI5 is allowed to dissociate into PCI3 and Cl₂ at 523 K. At equilibrium, [PCI5] = 0.171 M, and [PCI3] [Cl₂] = 9.24x10-2 M. Additional PCIs is added so that [PCI5]new = 0.314 M and = the system is allowed to once again reach equilibrium. PCI5 (9) =PC13(9) + Cl₂(9) K = 5.01x10-2 at 523 K (a) In which direction will the reaction proceed to reach equilibrium? | (b) What are the new concentrations of reactants and products after the system reaches equilibrium? [PCI5] = M [PCI3] = M [Cl₂] = M
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