temperature is 21 degrees Celsius, the temperature of Kelvin is 294.15 Kelvin,  the barometric pressure is 751mm Hg, calculate the vapor pressure

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The temperature is 21 degrees Celsius, the temperature of Kelvin is 294.15 Kelvin,  the barometric pressure is 751mm Hg, calculate the vapor pressure of water.

Prelaboratory Assignment: Analysis of an Aluminum-Zinc Alloy
1. On the following page, construct a graph of N vs % Al. To do this, refer to equation 5 and
the discussion preceding it. Calculate N for % Al 0, 25, 50, 75, and 100. Place these points
on the graph and Draw the best straight line between them.
%3D
2. A student obtained the following information from this experiment. Complete the chart:
Mass of Capsule
0.1168
Temperature
21c
Capsule + Alloy
0.3522 g
Temperature K
0.235니 g
Barometric
Pressure
Mass of Alloy
751 mm Hg
Mass of Empty
Beaker
Vapor Pressure of
Water (Table 2)
141.2 g_
mm Hg
Beaker + Water
388.3 g
Pressure of H,
atm
Mass of Water
247.18
Volume of Water
0.247/ mL
Volume H, =Volume displaced water =
Moles H, evolved (equation 6)
Liters
moles
Moles H,/g
N, moles of H, per gram of sample
h29
% Al from graph in problem 1
% Al from equation 5
75
Transcribed Image Text:Prelaboratory Assignment: Analysis of an Aluminum-Zinc Alloy 1. On the following page, construct a graph of N vs % Al. To do this, refer to equation 5 and the discussion preceding it. Calculate N for % Al 0, 25, 50, 75, and 100. Place these points on the graph and Draw the best straight line between them. %3D 2. A student obtained the following information from this experiment. Complete the chart: Mass of Capsule 0.1168 Temperature 21c Capsule + Alloy 0.3522 g Temperature K 0.235니 g Barometric Pressure Mass of Alloy 751 mm Hg Mass of Empty Beaker Vapor Pressure of Water (Table 2) 141.2 g_ mm Hg Beaker + Water 388.3 g Pressure of H, atm Mass of Water 247.18 Volume of Water 0.247/ mL Volume H, =Volume displaced water = Moles H, evolved (equation 6) Liters moles Moles H,/g N, moles of H, per gram of sample h29 % Al from graph in problem 1 % Al from equation 5 75
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