The balanced equation for the combustion of butane, CAH10, is shown below. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 CH10(g) + 13 02(g) --> 8 CO,2(g) 10 H20(1) 58.124 32 44.011 18.016

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter21: The Chemistry Of The Main Group Elements
Section: Chapter Questions
Problem 120IL
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The balanced equation below shows a simple way of manufacturing hydrogen gas in lab (you've done thisl). For your convenience, the molar
mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation:
2 Al(s) + 6 HCI(aq) -> 2 AICI3(aq) + 3 H2(g)
26.982
36.461
133.341
2.016
What volume of hydrogen gas, in mL, would be created by the reaction of 832 mg of hydrochloric acid with excess aluminum metal?
Transcribed Image Text:The balanced equation below shows a simple way of manufacturing hydrogen gas in lab (you've done thisl). For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 Al(s) + 6 HCI(aq) -> 2 AICI3(aq) + 3 H2(g) 26.982 36.461 133.341 2.016 What volume of hydrogen gas, in mL, would be created by the reaction of 832 mg of hydrochloric acid with excess aluminum metal?
The balanced equation for the combustion of butane, CAH10, is shown below. For your convenience, the molar mass of each substance is
shown below their formulas (in purple). Use this information to make the requested calculation:
2 CAH10(g) + 13 02(g) --> 8 CO2(g) + 10 H20(1)
58.124
32
44.011
18.016
How many liters of oxygen gas would be necessary to burn 18.2 g of butane?
Transcribed Image Text:The balanced equation for the combustion of butane, CAH10, is shown below. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 CAH10(g) + 13 02(g) --> 8 CO2(g) + 10 H20(1) 58.124 32 44.011 18.016 How many liters of oxygen gas would be necessary to burn 18.2 g of butane?
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