the blank(s) provided. 9. The y-intercept of the function f(x)=4(2) is 10. To the nearest hundredth, the value of x that satisfies the equation 5¹-625-1 is Use the following information to answer question 11. Tyler solved 64 = 4(2)²1 by expressing both sides as powers with the same base. His work is shown below. Step 1 Step 2 Step 3 Step 4 11. Tyler made his first error in Step 64=4(2) -4(2) 64-82 8² - 8²1 2 = 21 1=42
the blank(s) provided. 9. The y-intercept of the function f(x)=4(2) is 10. To the nearest hundredth, the value of x that satisfies the equation 5¹-625-1 is Use the following information to answer question 11. Tyler solved 64 = 4(2)²1 by expressing both sides as powers with the same base. His work is shown below. Step 1 Step 2 Step 3 Step 4 11. Tyler made his first error in Step 64=4(2) -4(2) 64-82 8² - 8²1 2 = 21 1=42
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter12: Quadratic Functions
Section12.6: Solving Problems Involving Quadratic Equations
Problem 14P
Related questions
Question
please do 9, 10 and 11
![the blank(s) provided.
9. The y-intercept of the function f(x)=4(2) is
10. To the nearest hundredth, the value of x that satisfies the equation 5¹-625- is
Use the following information to answer question 11.
Tyler solved 64 = 4(2) 21 by expressing both sides as powers with the same
base. His work is shown below.
Step 1
Step 2
Step 3
Step 4
11. Tyler made his first error in Step
= 4(2)²
64 4(2)
64-8²1
2 = 21
1=42](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5cafdb60-7d1d-4699-94a3-8fee7de7f9f5%2Fa4415beb-b77d-457a-b18b-f1a52c26eee0%2Forbr0a9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:the blank(s) provided.
9. The y-intercept of the function f(x)=4(2) is
10. To the nearest hundredth, the value of x that satisfies the equation 5¹-625- is
Use the following information to answer question 11.
Tyler solved 64 = 4(2) 21 by expressing both sides as powers with the same
base. His work is shown below.
Step 1
Step 2
Step 3
Step 4
11. Tyler made his first error in Step
= 4(2)²
64 4(2)
64-8²1
2 = 21
1=42
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