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The curve x² - 5y³ + 5x – 2y = -6 is shown in the graph below in blue. Use the graph below to draw line tangent to the curve at the point (-3,0). Submit your answer by dragging the black point such that the drawn tangent line (shown in red) matches the equation for it. Provide your answer below: (-6, 7) -10 -5 (-3,0) 10 -5 0 -5- -10 5 10

The curve x² - 5y³ + 5x – 2y = -6 is shown in the graph below in blue. Use the graph below to draw line tangent to the curve at the point (-3,0). Submit your answer by dragging the black point such that the drawn tangent line (shown in red) matches the equation for it. Provide your answer below: (-6, 7) -10 -5 (-3,0) 10 -5 0 -5- -10 5 10

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.3: Parallel And Perpendicular Lines
Problem 32PPS
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The curve x² - 5y3³ + 5x – 2y = −6 is shown in the graph below in blue. Use the graph below to draw line tangent to the curve at the point (-3,0). Submit your answer by dragging the black point such that the drawn tangent line (shown in red) matches the equation for it. Provide your answer below: (−6, 7) -10 -5 (-3,0) 10 5 0 -5- -10 5 10
Transcribed Image Text:The curve x² - 5y3³ + 5x – 2y = −6 is shown in the graph below in blue. Use the graph below to draw line tangent to the curve at the point (-3,0). Submit your answer by dragging the black point such that the drawn tangent line (shown in red) matches the equation for it. Provide your answer below: (−6, 7) -10 -5 (-3,0) 10 5 0 -5- -10 5 10
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