The factor of safety for a machine element depends on the particular point selected for analysis. For the bar and loading, shown in figure below, we need to have a minimum factor of safety, ηy = 2.5. The bar is to be made of AISI 1050 cold-drawn steel and is loaded by F = 2.65 kN, P = 10.5 kN, and T = 52 N-m.  Draw planar stress elements (A and B) showing normal and shear stresses at their proper orientations. Determine a safe diameter d to the nearest mm, based upon the distortion-energy theory, for both stress elements at A and B of the member shown in the figure.  Determine the safe diameter, d, based on maximum shear stress theory.  You are the designer, and you are to decide on the safe diameter, chosen from one of the diameters obtained from different failure theories used in parts (b) and (c) above, and explain your final decision made on the diameter.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter11: Columns
Section: Chapter Questions
Problem 11.2.15P: Repeat Problem 11.2-14 using L = 12 ft, ß = 0.25 kips/in., ßRl= 1.5ßL2, and ßR2= 2 ßR1.
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The factor of safety for a machine element depends on the particular point selected for analysis. For the bar and loading, shown in figure below, we need to have a minimum factor of safety, ηy = 2.5. The bar is to be made of AISI 1050 cold-drawn steel and is loaded by F = 2.65 kN, P = 10.5 kN, and T = 52 N-m. 

  1. Draw planar stress elements (A and B) showing normal and shear stresses at their proper orientations.
  2. Determine a safe diameter d to the nearest mm, based upon the distortion-energy theory, for both stress elements at A and B of the member shown in the figure. 
  3. Determine the safe diameter, d, based on maximum shear stress theory. 
  4. You are the designer, and you are to decide on the safe diameter, chosen from one of the diameters obtained from different failure theories used in parts (b) and (c) above, and explain your final decision made on the diameter. 
32M
32T
Obending
T torsion
P.
Tvert.shear = 5
4 L
3А
ахial
A
o' = o - 0,ơp
(o?
+o? + 3t)
%3D
xy
Ssy = 0.5 Sy
y
250 mm
A
B
F
d
T P
Transcribed Image Text:32M 32T Obending T torsion P. Tvert.shear = 5 4 L 3А ахial A o' = o - 0,ơp (o? +o? + 3t) %3D xy Ssy = 0.5 Sy y 250 mm A B F d T P
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