The following energy balance was developed: k a²T pC, მs2 s дт = 40 R Oz subject to the boundary conditions T(z = 0, s) To = T(z,so) = To T(z, s = 0) Tw a. Define the combined variable y = f = Convert the above model in terms of T, s, and z to one in terms of T and y. You will need to find f, a, and b that converts the PDE into the ODE: d²T + 0 dy2 dy subject to the transformed boundary conditions. b. Derive an expression (which will be in integral form) for T(s, z).

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The following energy balance was developed:
k 8²T
S ƏT
4vo Raz
pC» მs2
subject to the boundary conditions
a.
T(z = 0, s) = To
T(z,s → ∞0) = To
T(z, s = 0) Tw
=
Define the combined variable
y
= f ²2/16
sa
=
Convert the above model in terms of T, s, and z to one in terms of T and y. You
will need to find f, a, and b that converts the PDE into the ODE:
d²T
dy²
y². = 0
dy
subject to the transformed boundary conditions.
b. Derive an expression (which will be in integral form) for T(s, z).
Transcribed Image Text:The following energy balance was developed: k 8²T S ƏT 4vo Raz pC» მs2 subject to the boundary conditions a. T(z = 0, s) = To T(z,s → ∞0) = To T(z, s = 0) Tw = Define the combined variable y = f ²2/16 sa = Convert the above model in terms of T, s, and z to one in terms of T and y. You will need to find f, a, and b that converts the PDE into the ODE: d²T dy² y². = 0 dy subject to the transformed boundary conditions. b. Derive an expression (which will be in integral form) for T(s, z).
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