The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? The change in entropy in cal?

The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? The change in entropy in cal?

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter3: The First Law Of Thermodynamics

Section: Chapter Questions

Problem 86AP: Five moles of a monatomic ideal gas in a cylinder at 27 is expanded isothermally from a volume of 5...

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The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If I mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? c. The change in entropy in cal? Note that 1 literxatmosphere is equal to 101.325 joule.
The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? c. The change in entropy in cal? Note Note that 1 literxatmosphere is equal to 101.325 joule. Sol": given Heat of melting ice at 1 atm pressure = 1.4363 kca kcal/ 2 = 1.4363 kcal/mole mole volume of ice = 0·0196 lts " water = 0.018 lts @ work done is define as w=pdv » w = P(V₁ hot W = 1 (0·018-00196) W = 0·0016 Cal Pay Kat Ans
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