The histone protein H4 from cows and the H4 from p representing groups that diverged from one another billion years ago, differ by only two amino acid residu 102 total residues. The changes are conservative - thymus H4 is replaced by an lle in peas: Iys77 in the
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- A research focused on the number of illnesses involving the organism Escherichia coli (01257:H7), which causes a breakdown of red blood cells and intestinal hemorrhage in its victims. According to the Center for Disease Control of the Department of Health, an estimated 73,000 cases of E. coli infection and 61 deaths occur in Region Y. A 2028 outbreak traced to wild pigs, who spread the bacteria into a cabbage field in that , sickened 204 people in 26 municipalities. Outbreaks have occurred at a rate of 2.5 per 100,000. Let us suppose that this rate has not changed.a. What is the probability that at most five cases of E.coli per 100,000 are reported in California this year?b. What is the probability that more than five cases of E. coli are reported in California this year?c. Approximately 95% of occurrences of E. coli involve at most how many cases?Kuru is a prion disease of the Fore people of highland New Guinea. It was once transmitted by the consumption of deceased relatives at mortuary feasts, a ritual that was ended by about 1960. Using archived tissue samples, Mead et al. (2009) investigated genetic variants that might confer resistance to kuru. The data in the accompanying table are genotypes at codon 129 of the prion protein gene of young and elderly individuals all having the disease. Since the elderly individuals have survived long exposure to kuru, unusually common genotypes in this group might indicate resistant genotypes. b) Test whether genotype frequencies differ between the two age groups. Provide your answer below. (Your answer should include 1) null and alternative hypothesis, 2) degrees of freedom, 3) calculated chi-square value, 4) critical chi-square value (alpha=0.05) and 5) final biological conclusion)According to U.S. government statistics, mononucleosis (mono) is four times more common among college students than the rest of the population. Blood tests for the disease are not 100% accurate. Assume that the following table of data was obtained regarding students who came to a certain school's health center complaining of tiredness, a sore throat, and slight fever. Doesn't Have Mono 41 30 71 Has Mono 40 35 75 Totals 81 Positive Blood Test Negative Blood Test Totals 65 146 If a student is selected from this group, find the probability a student doesn't have mono, given that the test is positive. The probability is (Type an integer or decimal rounded to three decimal places as needed.) C
- According to U.S. government statistics, mononucleosis (mono) is four times more common among college students than the rest of the population. Blood tests for the disease are not 100% accurate. Assume that the following table of data was obtained regarding students who came to a certain school's health center complaining of tiredness, a sore throat, and slight fever. Has Mono Doesn't Have Mono Totals Positive Blood Test 19 44 63 Negative Blood Test 46 29 75 Totals 65 73 138 If a student is selected from this group, find the probability that the test is positive, given that the student has mono.Ophthalmology, Genetics Age-related macular degeneration (AMD) is a common eye disease among the elderly that can lead to partial or total loss of vision. It is well known that smoking and excessive weight tend to be associated with higher incidence rates of AMD. More recently, however, several genes have been found to be associated with AMD as well. One gene that has been considered is the Y402H gene (RS 1061170). There are three genotypes for the Y402H gene-TT, TC, and CC. Suppose the relationship between AMD and the Y402H genotype is as follows. Association between Y402H genotype and prevalence of AMD in a high-risk population Y402H TT (wild type) TC CC Total USE SALT AMD = yes 39 118 120 277 AMD = no 378 528 276 1,182 (a) What is the relative risk for AMD for the CC genotype compared with the TT genotype? (Round your answer to two decimal places.) (b) One issue is whether the Y402H gene is in Hardy-Weinberg equilibrium (HWE). For a gene to be in HWE, its two alleles must assort…Over the 200,000 years or so that modern humans have existed, human populations have adapted to a wide range of environments, including different foods. The researchers hypothesized that increased consumption of starch-rich foods during human evolutionary history gave individuals with multiple copies of the salivary amylase gene an "advantage." To test their hypothesis, Perry and colleagues analyzed DNA collected from two groups. The first group consisted of populations that have historically consumed a diet low in starch. The other group traditionally ate high-starch foods. The researchers measured the number of copies of the AMY 1 gene in individuals from these different populations. The descriptive statistics can be found below. Group High-Starch Diet 7.12 Low-Starch Diet 5.48 Sample Mean Sample Standard Deviation Sample Size 2.92 25 2.18 25 Assuming both groups come from normal populations, what is the 95% confidence interval on the mean difference between the groups (high – low)?…
- The recessive mutation bg (beige) in mice results in a decrease in the activity of natural killer cells in homozygous mutant mice. You test the hypothesis that this cell type plays an important role in rejection of tumor cells (derived from a tumor induced in an isogenic animal) by injecting animals with genotypes bg/bg or bg/+ with 106 cells and measuring the time required for the development of a palpable tumor in each animal. You obtain the following data: Time to tumor development (days) Genotype 28, 51, 47, 80 14, 35, 17, 37, 16 3. What is the most appropriate statistical approach to test the hypothesis? a. t-test for paired samples b. t-test for unpaired samples C. ANOVA d. Mann-Whitney U test e. Kruskal-Wallis test 4. Is there a significant difference in tumor latency between the two groups? bg/+ bg/bgFrom a 2019 article in the Journal of Nutrients, the following abstract was obtained: The Mediterranean diet is considered one of the most worldwide healthy dietary patterns thanks to a combination of foods rich mainly in antioxidants and anti-inflammatory nutrients Many studies have demonstrated a strong and inverse relationship between a high level of Mediterranean diet adherence and some chronic discases (such as cardiovascular diseases diabetes, etc.) and cancer. Given its protective effects in reducing oxidative and inflammatory processes of cells and avoiding DNA damages, cell proliferation, and their survival. angiogenesis, inflammations and metastasis, the Mediterrancan diet is considered a powerful and manageable method to fight cancer incidence. The aim of this narrative review was to determine the magnitude of interaction between the Mediterrancan diet and more widespread types of cancer so as to give a first and useful overview on this relationship identifying. with a…The genetic of a human is the source of a disese., but only if you have the gene type a. The relative frequency of people with carrying two copies of a is 0.0001(aa), but one copy is 0.0198(Aa). Those not having the a-gene = 0.9801(AA) Even though you are carrying a you may not get the disese. You can get the disese without a. the probability of aa = 0.6, Aa= 0.02 and AA= 0.01 What is the probability that a random person has the disese? Given you have the disese, whats the probabilty for having genes aa, Aa or AA?
- A population of 80 rats is tested for 4 genetic mutations after exposure to some chemicals: mutation A, mutation B, mutation C, and mutation D. 43 rats tested positive for mutation A. 37 rats tested positive for mutation B.39 rats tested positive for mutation C. 35 rats tested positive for mutation D. One rat tested positive for all four mutations. 5 rats tested positive for mutations A, B, and C. 4 rats tested positive for mutations A, B, and D. 6 rats tested positive for mutations A, C, and D.3 rats tested positive for mutations B, C, and D. 64 rats tested positive for mutations A or B. 63 rats tested positive for mutations A or C. 59 rats tested positive for mutations A or D. 58 rats tested positive for mutations B or C. 59 rats tested positive for mutations B or D. 60 tested positive for mutations C or D. 8 rats did not show any evidence of genetic mutation. What is the probability that if 5 rats are selected at random, 3 will have exactly 2 genetic mutations? Round your answer to…A geneticist working on peas has a single plant monohybrid Y/y (yellow) plant and, from a self of this plant,wants to produce a plant of genotype y/y to use as a tester. How many progeny plants need to be grown to be 95percent sure of obtaining at least one in the sample?As mentioned in Experimental Question E11, red eyes is the wildtype phenotype. Several different genes (with each gene existing intwo or more alleles) are known to affect eye color. One allelecauses purple eyes, and a different allele causes sepia eyes. Both ofthese alleles are recessive to red eye color. When flies with purpleeyes were crossed to flies with sepia eyes, all of the F1 offspringhad red eyes. When the F1 offspring were allowed to mate witheach other, the following data were obtained:146 purple eyes151 sepia eyes50 purplish sepia eyes444 red eyesExplain this pattern of inheritance. Conduct a chi sq
