The length of a rectangle is 5 more than thrice the width. If the perimeter is 106, what is its area? Answer: x = and y = Solution: let x width of the rectangle R: y = length of the rectangle Length E: = 3x + 5 width = x S P = 2L + 2W A: x = and y = Area of the rectangle = length x width A = square units C: P = 2L + 2W Answer GEOMETRIC PROBLEM The length of a rectangle is 5 more than thrice the width. If Answer: x = Answer: y = the perimeter is 106, what is its area? Answer: A = [c square units [a] [b]

The length of a rectangle is 5 more than thrice the width. If the perimeter is 106, what is its area? Answer: x = and y = Solution: let x width of the rectangle R: y = length of the rectangle Length E: = 3x + 5 width = x S P = 2L + 2W A: x = and y = Area of the rectangle = length x width A = square units C: P = 2L + 2W Answer GEOMETRIC PROBLEM The length of a rectangle is 5 more than thrice the width. If Answer: x = Answer: y = the perimeter is 106, what is its area? Answer: A = [c square units [a] [b]

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter3: Solving Equation And Problems

Section3.8: Proof In Algebra

Problem 1ST

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Similar questions

One side of a rectangle is 2 cm longer than a second side. If the area is 35cm2, find the dimensions of the rectangle.
The perimeter of a triangle is 30 in. The longest side is 2 less than 3 times the shortest side and the other side is 2 more than twice the shortest side. Find the length of each side.

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