The probability that the wave will crash onto the beach between 0.2 and 1 seconds after the person arrives is     P(0.22.96)=P(x>2.96)=   . Suppose that the person has already been standing at the shoreline for 0.1 seconds without a wave crashing in. Find the probability that it will take between 2.1 and 3.3 seconds for the wave to crash onto the shoreline.     P(2.10.1)=P(2.10.1)=

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter9: Solving Quadratic Functions
Section: Chapter Questions
Problem 4CA
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Today, the waves are crashing onto the beach every 5.3 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5.3 seconds. Round to 4 decimal places where possible.

  1. The probability that the wave will crash onto the beach between 0.2 and 1 seconds after the person arrives is
        P(0.2<x<1)=P(0.2<x<1)=   .
  2. The probability that it will take longer than 2.96 seconds for the wave to crash onto the beach after the person arrives is
        P(x>2.96)=P(x>2.96)=   .
  3. Suppose that the person has already been standing at the shoreline for 0.1 seconds without a wave crashing in. Find the probability that it will take between 2.1 and 3.3 seconds for the wave to crash onto the shoreline.
        P(2.1<x<3.3∣x>0.1)=P(2.1<x<3.3∣x>0.1)=   .
  4. 79% of the time a person will wait at least how long before the wave crashes in?
         seconds.
  5. Find the maximum for the lower quarter.
          seconds.
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