The zeros in the given matrix make its characteristic polynomial easy to calculate. Find the general solution of x' = Ax. 1 00 0 -9-29 -3 A = 0 0 2 0 0 09-1 x(t)=

Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.CR: Review Exercises
Problem 15CR: For what values of a does the matrix A=[01a1] have the characteristics below? a A has eigenvalue of...
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The zeros in the given matrix make its characteristic polynomial easy to calculate. Find the general solution of x' = Ax.
1
0
0 0
9 -2
9-3
A =
0
0
2 0
0
0 -9-1
x(t) =
-
HT
Transcribed Image Text:The zeros in the given matrix make its characteristic polynomial easy to calculate. Find the general solution of x' = Ax. 1 0 0 0 9 -2 9-3 A = 0 0 2 0 0 0 -9-1 x(t) = - HT
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