2.A[x] → (Vx)A[x] is NOT atheorem if x indeed occurs free in A.Yet, I think I got a proof: First, let me use DThm and prove insteadA[a] F (Vx)A[x]:1) A[a]2) (Væ)A[x] (1 + Gen)(hyp)Something must be wrong in my “PROOF"! What EXACTLY

1. Ax=h+p 2.∀x.Ax 1.Universal Generalization on 3. Ax→∀x Ax 1,2 Introduction.

Answered: theorem if Yet, I think I

Math

Advanced Math

theorem if Yet, I think I

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter3: Functions And Graphs

Section3.5: Graphs Of Functions

Problem 56E

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Question

2.
A[x] → (Vx)A[x] is NOT a
theorem if x indeed occurs free in A.
Yet, I think I got a proof: First, let me use DThm and prove instead
A[a] F (Vx)A[x]:
1) A[a]
2) (Væ)A[x] (1 + Gen)
(hyp)
Something must be wrong in my “PROOF"! What EXACTLY

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