There are 3 strategies to solve the turbulent flows in conduits, which are as follows: Case 1 Case 2 goal given Case 3 goal given - find h, L, D and Q - find Q -h, Land D goal - find D given - Q. L and h, For cases 2 and 3, there are direct equations available as follows: For Case 2 iterative approach can be avoided sometimes by using eq as: For Case 3 iterative approach can also be eliminated sometimes by using eq as Q=-2.22D2 √gh,/Llog + D=0.66 2 k 1.78v 3.7D Dgh, L 4.75 (20) "* + 10% ( ( gh Select the most appropriate statement. L gh, 327000 O If he is not available, you need to assume he and then solve those equations for Q and D. Once you obtained Q and D, you need to check whether that Q and D are correctly assumed or not, if not you need to re-assume h, until the solution converged. If he is available, you can solve those equations for Q and D directly. O All the statements are correct. O For Case 1, we can get h; directly from Darch-Weishbach eq.
There are 3 strategies to solve the turbulent flows in conduits, which are as follows: Case 1 Case 2 goal given Case 3 goal given - find h, L, D and Q - find Q -h, Land D goal - find D given - Q. L and h, For cases 2 and 3, there are direct equations available as follows: For Case 2 iterative approach can be avoided sometimes by using eq as: For Case 3 iterative approach can also be eliminated sometimes by using eq as Q=-2.22D2 √gh,/Llog + D=0.66 2 k 1.78v 3.7D Dgh, L 4.75 (20) "* + 10% ( ( gh Select the most appropriate statement. L gh, 327000 O If he is not available, you need to assume he and then solve those equations for Q and D. Once you obtained Q and D, you need to check whether that Q and D are correctly assumed or not, if not you need to re-assume h, until the solution converged. If he is available, you can solve those equations for Q and D directly. O All the statements are correct. O For Case 1, we can get h; directly from Darch-Weishbach eq.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![There are 3 strategies to solve the turbulent flows in conduits,
which are as follows:
Case 1
Case 2
Case 3
goal
given
goal
given
- find h,
L, D and Q
- find Q
-h, L and D
goal
- find D
given - Q, L and h,
For cases 2 and 3, there are direct equations available as follows:
For Case 2
iterative approach can be
avoided sometimes by
using eq as:
For Case 3
iterative approach can also
be eliminated sometimes
by using eq as
Q=-2.22D25 √gh, /Llog +
D=0.66 k
LO²
ghy
Select the most appropriate statement.
k
1.78v
3.7D D √gh, IL
4.75
All the statements are correct.
+10%
L
gh,
3.27000
If he is not available, you need to assume h; and then solve those
equations for Q and D. Once you obtained Q and D, you need to
check whether that Q and D are correctly assumed or not, if not you
need to re-assume h, until the solution converged.
O If h, is available, you can solve those equations for Q and D
directly.
For Case 1, we can get he directly from Darch-Weishbach eq.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb1e90be5-cf6c-4231-9fcc-c208c8ec9493%2Fc620125d-7052-4ce9-a11a-fffb85c7c405%2F0zccz2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:There are 3 strategies to solve the turbulent flows in conduits,
which are as follows:
Case 1
Case 2
Case 3
goal
given
goal
given
- find h,
L, D and Q
- find Q
-h, L and D
goal
- find D
given - Q, L and h,
For cases 2 and 3, there are direct equations available as follows:
For Case 2
iterative approach can be
avoided sometimes by
using eq as:
For Case 3
iterative approach can also
be eliminated sometimes
by using eq as
Q=-2.22D25 √gh, /Llog +
D=0.66 k
LO²
ghy
Select the most appropriate statement.
k
1.78v
3.7D D √gh, IL
4.75
All the statements are correct.
+10%
L
gh,
3.27000
If he is not available, you need to assume h; and then solve those
equations for Q and D. Once you obtained Q and D, you need to
check whether that Q and D are correctly assumed or not, if not you
need to re-assume h, until the solution converged.
O If h, is available, you can solve those equations for Q and D
directly.
For Case 1, we can get he directly from Darch-Weishbach eq.
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